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2 years ago

What two number multiply to 24 and add to -11

Mathematics

2 answers:

natali 33 [55]2 years ago

7 0

Answer:

One example is x = -8, y = -3

Step-by-step explanation:

Lets make a system of equations.

Let x be the first number and y be the second.

x * y = 24

x + y = -11

Solve for x and substitute.

x = 24/y

24/y + y = -11

24 + y^2 = -11y

y^2 + 11y + 24 = 0

Factor.

(y + 8)(y+3) = 0

So one example is x = -8, y = -3

enot [183]2 years ago

4 0

Answer:

8 and 3

Step-by-step explanation:

Brainliest Please

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Need help, extra points

castortr0y [4]

Answer:

around 35-42° it's one of them 2 probably 40-41°

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3 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

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3 years ago

How to calculate a probability

Lelu [443]

Probability is calculated by comparing the odds to a certain event occurring to the number of possible events.

P= $\frac{possibility-of-an-event-occuring}{number-of-total-outcomes}$

For example, take a six-sided dice number 1-6 on each side. The probability of rolling a 4 would be1 in 6 or 1/6. This is because of the six possible outcomes, rolling a 4 is only one of them.

P(4)=1/6

Now take the same dice. The probability of rolling an even number is 3/6. To see why, lets look at the total possible outcomes:

1
2
3
4
5
6

Of the 6 possibilities, 3 are even numbers.

P(even)=3/6 or 1/2

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2 years ago

Which fraction is greater,2⁄3or1⁄3 ? How do you now?

m_a_m_a [10]

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mojhsa [17]

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1 year ago