How do you create common denominator so you can compare fractions

1 answer:

7 0

Find a common denominator by multiplying the denominators together. Use that common denominator to create equivalent fractions. Then, compare the numerators to figure out which is bigger

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HEY hey hellooo HELP ME!!

Bezzdna [24]

Answer:

1, 6, 11, 16, 21, 26, 31, 36, 41, 46, 51, 56, 61, 66, 71.

6 0

2 years ago

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Solve for x in the equation

Viktor [21]

Answer:

${x}^{2} + 2x + 1 = 17 \\ {x}^{2} + 2x - 16 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 2± \sqrt{68} }{2} \\ x = \frac{ - 2±2 \sqrt{17} }{2 } \\ x = - 1± \sqrt{17}$

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3 years ago

Can you help me please?

PilotLPTM [1.2K]

Answer:

Your answer should be 0.125

Step-by-step explanation:

Divide the numerator by the denominator

1 divided by 8 = 0.125

I see you're from k12. Hello, fellow homeschooler. Good luck on the assignment!

5 0

2 years ago

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$