of would be needed to make 150 mL of 0.300 M solution.
Further Explanation:
The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.
The formula to calculate the molarity of solution is as follows:
......(1)
Rearrange equation (1) to calculate the moles of .
......(2)
The volume of solution is to be converted into L. The conversion factor for this is,
So the volume of solution is calculated as follows:
The molarity of solution is 0.300 M.
The volume of solution is 0.15 L.
Substitute these values in equation (2).
The formula to calculate the mass of is as follows:
......(3)
Substitute 0.045 mol for the moles of and 159.609 g/mol for the molar mass of in equation (3).
Therefore the mass of is 7.182 g.
Learn more:
1. Calculation of volume of gas: brainly.com/question/3636135
2. Determine the moles of water produced: brainly.com/question/1405182
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: molarity, CuSO4, dilution, moles of CuSO4, volume, solution, 0.045 mol, 150 mL, 0.300 M, 7.182 g, 159.609 g/mol, 0.15 L.