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3 years ago

How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?

Chemistry

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

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Compare natural selection to evolution. Be sure to justify your response in two or more complete sentences in the essay

Wittaler [7]

Answer:

Natural selection is a process in which organisms are fit to adapt and live in the environment. Natural selection was an idea developed by Charles Darwin, Darwin contributed this idea when he was studying birds and tortoises at the Galapagos Islands. He then wrote his famous book, Origin of Species. Evolution is also very similar, evolution is a process in which organisms reproduce and mutate in order to survive and adapt. As you can see, natural selection and evolution are alike in many ways.

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2 years ago

Determine what kind of diet this animal has by examining its teeth.

Marysya12 [62]

Answer:

That animal is a Carnivore.

Explanation:

The skull is that of a Panther which is a carnivore. Hope this helps

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2 years ago

Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl

77julia77 [94]

Answer:

0.37M

Explanation:

Since sulfuric acid, H₂SO₄, is a diprotic acid and potassum hydroxide, KOH, contains one OH⁻ in the formula, the number of moles of potassium hydroxide must be twice the number of moles of sulfuric acid.

1. Determine the number of moles of KOH in 47mL of 0.39M potassium hydroxide solution

number of moles = molarity × volume in liters

number of moles = 0.39M × 47mL × 1liter/1,000 mL = 0.1833mol

2. Determine the number of moles of sulfuric acid needed

number of moles of H₂SO₄ = number of moles of KOH/2 = 0.1833/2 = 0.009165mol

3. Determine the concentration that contains 0.009165 mol in 25mL of the acid.

Molarity = number of moles / volume in liters

M = 0.009165mol/(25mL) × (1,000mL/liter) = 0.3666M

Round to two significant figures: 0.37M

7 0

3 years ago

How many grams of NaCl do you need to prepare 200 ml of a 5M solution? The molecular weight of NaCl is 58.4 g/mol. Smol 0.2L-1mo

Butoxors [25]

Answer:

The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

Molarity = (# of moles ) / volume

# of moles = Molarity x volume

# of moles = 5 x 0.2

# of moles = 1

58.4 g ---------------------- 1 mol

x --------------------- 1 mol

x = (1 x 58.4) / 1

x = 58.4 g of NaCl

4 0

3 years ago

Select the correct answer from each drop-down menu. consider the substances hydrogen (h2), fluorine (f2), and hydrogen fluoride

nasty-shy [4]

The boiling point of HF is higher than the boiling point of $H_2$ , and it is higher than the boiling point of $F_2$ .

<h3>What is the boiling point?</h3>

The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.

$F_2$ has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between $H^+$ and $F^-$ ions.

Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.

$H_2$ and $F_2$ will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.

Hence, the boiling point of HF is higher than the boiling point of $H_2$ , and it is higher than the boiling point of $F_2$ .

Learn more about the boiling point:

brainly.com/question/25777663

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7 0

1 year ago