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ludmilkaskok [199]
3 years ago
12

What object does a scientist use to measure liters

Chemistry
1 answer:
Arturiano [62]3 years ago
4 0
Liter measures liquid- so a measuring cup
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How many sulfate ions are there in 321 grams of iron lll sulfate
nikitadnepr [17]
Here, we use the mole as we would use any other collective number: a dozen eggs; a Bakers' dozen; a Botany Bay dozen.
Of course, the mole specifies a much larger quantity, and if I have a mole of stuff then I have
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individual items of that stuff. We can also specify an equivalent mass, because we also know the mass of a mole of iron, and a mole of oxygen etc........The mole is thus the link between the macro world of grams and kilograms and litres, that which we can measure out in the lab, to the micro world of atoms, and molecules, that which we can perceive only indirectly.
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2 years ago
When metals react with acid, bubbles of what gas are produced?​
elena-14-01-66 [18.8K]

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hydrogen is the answer

5 0
3 years ago
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The heat of fusion for water is 80. cal/g. how many calories of heat are released
Ray Of Light [21]

800 calories are released


7 0
3 years ago
A chemist dissolved crystals of an unknown substance into water at room temperature. He found that 33 g of the substance can be
Inga [223]
The answer is: It's solubility
8 0
4 years ago
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A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
4 years ago
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