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Elena L [17]
3 years ago
7

In the heating curve of an unknown substance, the line labeled C represents what change(s)?

Chemistry
2 answers:
IceJOKER [234]3 years ago
6 0

Answer:

C) Temperature and Kinetic Energy.

Explanation:

Hello there!

In this case, according to the generic heating curve on the attached file, it possible to see that on the point C, whereas the line is diagonal, the temperature increases, but also the kinetic energy increases because the molecules gain energy due to the increase of the temperature. It is important to say that on flat lines, like those on B and D, the phase change takes place and just the potential energy change.

In such a way, we infer that the answer is C) Temperature and Kinetic Energy.

Best regards!

den301095 [7]3 years ago
5 0

Answer:

C) Temperature and Kinetic Energy.

Explanation:

In the heating curve of an unknown substance, the line labeled C represents <u>Temperature and Kinetic Energy.</u>

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What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

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To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

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8 0
3 years ago
Chemicals (and humans) are all about what
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Answer:

Atoms, and chemical make up

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4 0
3 years ago
Read 2 more answers
(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

6 0
3 years ago
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