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3 years ago

What's the slope of this line? Someone plz answer plz.

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

Answer:

0.5

Step-by-step explanation:

saveliy_v [14]3 years ago

4 0

Answer:

$\frac{1}{2}x + 5$

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What is 3-4+11+21-3? Best explained answer gets Brainliest!!!! Good luck :)

Alika [10]

Answer:

See below

Step-by-step explanation:

Let's take it part by part:

(3-4)+(11+21)-3

-1+(32)-3

-4+32

6 0

3 years ago

Read 2 more answers

Seth has a bank account which pays 1.01% interest, compounded quarterly. Seth withdraws $4,567 from the account every quarter fo

dimulka [17.4K]

Answer:

C. $538,021.66

Step-by-step explanation:

It is given that the money Seth withdraws was compounded every quarter for 35 years. So, we get,

Amount withdrawn every quarter, P = $4567

Rate of interest, r = $\frac{0.0101}{4}$ = 0.002525

Time period, n = 35 × 4 = 140

Now, as we know the formula for annuity as,

$P=\frac{r \times PV}{1-(1+r)^{-n}}$

where P = installments, PV = present value, r = rate of interest and n = time period.

This gives, $PV=\frac{P \times [1-(1+r)^{-n}]}{r}$

i.e. $PV=\frac{4567 \times [1-(1+0.002525)^{-140}]}{0.002525}$

i.e. $PV=\frac{4567 \times [1-(1.002525)^{-140}]}{0.002525}$

i.e. $PV=\frac{4567 \times [1-0.7021]}{0.002525}$

i.e. $PV=\frac{4567 \times 0.2975}{0.002525}$

i.e. $PV=\frac{1358.68}{0.002525}$

i.e. $PV=538,091.08$

So, the closest answer to initial value of the account is $538,021.66

Hence, option C is correct.

6 0

3 years ago

Read 2 more answers

Rowing upstream for 5 mi against a strong current, your speed is 20% less than your normal rowing speed. On the return trip down

spayn [35]

Answer:

it would be the same as rowing normal speed because you loose 20% for 5 mi and gain 20% back for 5 mi

Step-by-step explanation:

3 0

3 years ago

5 x [(28-4) - (4 + 3)]

igomit [66]

Answer:

85x

Step-by-step explanation:

Add 4 and 3 . 5 x ( 28 − 4 − 1 * 7 ) Multiply − 1 by 7.

5 x ( 28 − 4 − 7 )

Simplify the expression. Subtract 4 from 28.

5 x ( 24 − 7 )

Subtract 7 from 24.

5 x * 17

Multiply 17 by 5.

85 x

8 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago