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beks73 [17]
2 years ago
5

jesse drive 6 3/8 miles in a golf cart during a round of golf. Payton drives 7 3/4 miles . how much father dose payton drives

Mathematics
2 answers:
slava [35]2 years ago
4 0
Hello!  To answer your question, on how much farther Payton drives than Jesse, you need to understand the needed operation for this problem.  From the given problem, you can assume that 7 3/4 is a bigger fraction than Jesse's 6 3/8.  Once you figure out which operation is needed to find out how much more Peyton drove, you want to make both mixed numbers into inproper fractions.  To make a mixed number into an improper fraction, you multiple the whole number by the denometer and add the product to the numeratior.  Think of it as going around a clock if that helps.  Once they are both improper, give them both a common denometer (if needed).  Once you do that, you use the operation you decided on earlier; multiplication, division, addition, or subtraction.  If you have any other questions on my answer, or any information I've given, feel free to shoot me a message or another question.  I hope this helped, good luck!
Serjik [45]2 years ago
4 0
He drives a mile and 3/8 further than Jesse.
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6 0
3 years ago
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Ne4ueva [31]
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2 years ago
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Tatiana [17]

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6 0
3 years ago
Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions
forsale [732]

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

8 0
3 years ago
The cargo carrying part of Billy‘s truck has a length of 8.3 m a width of 3 m and a height of 4.2 m. What is the maximum volume
madam [21]
You're really just finding the volume of the cargo-carry part.

V= L x W x H

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ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
8 0
3 years ago
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