I need help solving quadratics

Mathematics

1 answer:

jolli1 [7]3 years ago

8 0

Quadratic equations are the equations that can be re arranged in the linear or the standard form.

Explanation:

In algebra, a quadratic equation is any condition that can be adjusted in standard structure as where x speaks to an unknown, and a, b, and c speak to known numbers, where a ≠ 0. On the off chance that a = 0, at that point the condition is straight, not quadratic, as there is no term.

Quadratic equations are really utilized in regular day to day existence, as while ascertaining regions, deciding an item's benefit or figuring the speed of an article. Quadratic conditions allude to conditions with in any event one squared variable, with the most standard structure being ax² + bx + c = 0.

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Simplify 3f-2f+f I need a answer for that please

vlada-n [284]

Answer:

Step-by-step explanation:

3f-2f+f | Given

1f + f | Subtract 3f and 2f

2f | Add 1f and 1f.

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2 years ago

What is the value of x?

allsm [11]

First need to find the length of line LJ

Line LJ = 8sqrt2 * sin(30) = 5.6569

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3 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.(a)Compute the probability of randomly selecting

Aneli [31]

a. There are four 5s that can be drawn, and $\binom43=4$ ways of drawing any three of them. There are $\binom{52}3=22,100$ ways of drawing any three cards from the deck. So the probability of drawing three 5s is

$\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018$

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of $\frac8{52}=\frac2{13}\approx0.15$ of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability $\frac{12}{52}=\frac3{13}\approx0.23$ of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of $\frac{16}{52}=\frac4{13}\approx0.31$ .