Question

Find the missing side lengths. Answers are in simplest radical form with the denominator rationalized

Answer 1

Answer:

Option B.

Step-by-step explanation:

The given triangle is a right angle triangle.

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

In the given triangle,

$\tan (45^{\circ})=\dfrac{v}{7}$

$1=\dfrac{v}{7}$

$7=v$

Using Pythagoras theorem, we get

$hypotenuse^2=Perpendicular^2+Base^2$

$u^2=v^2+7^2$

$u^2=7^2+7^2$

$u^2=2(7^2)$

Taking square root on both sides, we get

$u=\sqrt{2(7^2)}$

$u=7\sqrt{2}$

Therefore, the correct option is B.