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2 years ago

11

Ninety-one students signed up for the skating club. Coach Link wants to form teams with the same number of members on each team,

but says that is impossible: the only teams he can make are 91 teams of 1 or 1 team of 91. Is coach link correct?

2 answers:

iragen [17]2 years ago

6 0

No, he's incorrect, because 91 students can be in 7 groups of 13 or 13 groups of 7.

romanna [79]2 years ago

4 0

Answer: he is not right

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Marlin bought 4 ham sandwiches and 2 bags of chips for $22.50 . If the chips cost $0.75 per bag how much did each sandwich cost

Masteriza [31]

first work out the value of 2 bags of chips which is: 0.75 + 0.75 = 1.50p

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since what is left (21) is how much 4 ham sandwiches cost we can just divide 21 by 4 which is 5.25

so each sandwich costs 5.25 pounds

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anastassius [24]

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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Sarah got a 80% on her pre algebra final exam. if there were 75 questions total how many did sarah get correc? How many did she

stepladder [879]

She got 60 correct and 15 wrong. She got 11.25% wrong

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faust18 [17]

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0.4:17.2 is congruent to 1:43.

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I hope this helps!
~kaikers

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