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valkas [14]
3 years ago
11

Which expression is equal to (−12−2i)+(2+2i)?

Mathematics
1 answer:
Step2247 [10]3 years ago
6 0
(-12 - 2i) + (2 + 2i)
= -12 - 2i + 2 + 2i
= -12 + 2 - 2i + 2i
= -10

Answer: -10
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12 / 0.96 please answer this i need it​
dimaraw [331]

Answer:

12.5

Step-by-step explanation:

4 0
3 years ago
6. Let f and g be differentiable functions
Julli [10]

Answer:

(b) 1

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To differentiate h(x)=f(x)g(x) we will need the product rule:

h'(x)=f'(x)g(x)+f(x)g'(x).

We have h'(x)=f(x)g'(x), so the following equation is true by the transitive property:

f'(x)g(x)+f(x)g'(x)=f(x)g'(x)

By subtraction property we have:

f'(x)g(x)=0

Since g(x) \neq 0, then we can divide both sides by g(x):

f'(x)=\frac{0}{g(x)}

f'(x)=0

This implies f(x) is constant.

So we have that f(x)=c where c is a real number.

Since f(0)=1 and f(0)=c, then by transitive property 1=c.

So f(x)=1.

Checking:

h(x)=1 \cdot g(x)

h'(x)=g'(x)=1 \cdot g'(x)

So the following conditions were met.

5 0
3 years ago
The equation of line v is y=9x+1. Line w is perpendicular to line v and passes through (3, – 2). What is the equation of line w?
Anna11 [10]

Answer:

Step-by-step explanation:

Remember the general form of a linear equartion: y=mx + b, where m is the slope and b is the y-intercept (the value of y when x = 0).

The equation of line v (y=9x+1) has a slope of 9. A perpendicular line with have a slope equal to the negative inverse of the reference line. So the line we want will have a slope of -(1/9). That gives us y = -(1/9)x + b. Any vale of b will produce a line that is perpendicular. But we want a line that goes through point (3,-2). All we need to do is find a value for b that will make that wish come true.

Use the point (3,-2) in y = -(1/9)x + b and solve for b:

y = -(1/9)x + b

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b = - 1 2/3, or -(5/3)

The equation is y = -(1/9)x + - (5/3)

7 0
2 years ago
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