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3 years ago

5

Jim is clearing out trees and planting grass to enlarge his backyard. He plans to double both the width and the length of his cu

rrent rectangular backyard, as shown.
a. How will the area of Jim's new backyard compare to the area of his current backyard? b. Will it take Jim twice as long to mow his new backyard then his old backyard? Explain. (Assume Jim mows at the same rate for both yards.)

1 answer:

Ierofanga [76]3 years ago

4 0

U should know the area of rectangle is w*l
if we increase it by double or times 2 its area will be
A=2w*2wl
A=4wl
area would be 4 times of original one
Now u can get the answer

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Solve 3x²-x-2=0. Please show all work.

lorasvet [3.4K]

3x²-x-2=0

Δ=1+24=25 (Δ=b²-4ac)

x₁,₂= $\frac{1(+/-)\sqrt{25} }{6}$

x₁,₂= $\frac{1(+/-)5}{6}$

x1= $\frac{1+5}{6}$ =6/6=1

x2= $\frac{1-5}{6}$ = $\frac{-2}{3}$

so

x1=1

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a circle has a circumstance of 20. it has an arc on length 4. what is the central angle of the arc in degrees?

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Answer:

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Step-by-step explanation:

If a circle has a circumference of 20 and an arc with a length of 4, we can simply set up a ratio to determine the angle of the arc in degrees:

$\frac{4}{20} = \frac{x}{360}$

Cross multiply:

$1440 = 20x\\$

Divide both sides by '20':

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Matthew made a fruit salad, in which the ratio of blueberries to red grapes is 8:6. Write the ratio of red grapes to blueberries

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Read 2 more answers

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

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