Answer:
XL(toluene) = 0.77
XL(benzene) = 0.23
Explanation: see attachment
Formula : BaI₂. <span>barium iodide</span>
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Hey There!</h2><h2>
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Answer:</h2><h2>
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ELECTROPLATING </h2>
Electroplating the plating one metal on to the another metal, It is mostly used for preventing corrosion by using copper or chromium or decorate the object by using gold or silver plating.
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<h3>Principle:</h3>
When electricity is passed the thin layer of metal is deposited on another metal and water molecule given out as a By-Product, Thus this process works on the principle of Hydrolysis.
<h2>_____________________________________</h2><h2>QUESTION:</h2>
A) Electrolysis
B) Chromium prevents corrosion and gives the fine shining touch to the objects.
C) The metal which is deposited to the object i.e. spoon will be connected to the positive electrode of a battery, Thus it is anode. The spoon at which electroplating is need to be done is connected to the negative electrode, thus the Spoon is cathode.
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Best Regards,</h2><h2>
'Borz'</h2>
Answer:
Explanation:
The given pH = 8.55
Unknown:
[H₃O⁺] = ?
[OH⁻] = ?
In order to find these unknowns we must first establish some relationship.
pH = -log[H₃O⁺]
8.55 = -log[H₃O⁺]
[H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³
To find the [OH⁻],
pH + pOH = 14
pOH = 14 - pH = 14 - 8.55
pOH = 5.45
pOH = -log[OH⁻]
[OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³
The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.
