Question

‍♀️always have problems with these

Answer 1

I hope that my hand writing is clear.

Answer 2

$y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have:

$(1,\ 5)\to x_1=1,\ y_1=5\\(2,\ 2)\to x_2=2,\ y_2=2$

Susbstitute:

$m=\dfrac{2-5}{2-1}=\dfrac{-3}{1}=-3$

$y=-3x+b$

Susbtitute the coordinates of the point (2, 2) to the equation:

$2=(-3)(2)+b\\\\2=-6+b\ \ \ \ |+6\\\\b=8$

Answer: y = -3x + 8