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Fantom [35]
3 years ago
11

‍♀️always have problems with these

Mathematics
2 answers:
inysia [295]3 years ago
5 0
I hope that my hand writing is clear.

Lana71 [14]3 years ago
4 0

y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have:

(1,\ 5)\to x_1=1,\ y_1=5\\(2,\ 2)\to x_2=2,\ y_2=2

Susbstitute:

m=\dfrac{2-5}{2-1}=\dfrac{-3}{1}=-3

y=-3x+b

Susbtitute the coordinates of the point (2, 2) to the equation:

2=(-3)(2)+b\\\\2=-6+b\ \ \ \ |+6\\\\b=8

<h2>Answer: y = -3x + 8</h2>
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ABC and AED are straight lines. BE and CD are parallel. AC = 12.3cm AB = 8.2cm BE = 3.8cm a) Work out length CD. AD = 9.15cm
elena-14-01-66 [18.8K]

Answer:

15.33cm

Step-by-step explanation:

when you try to draw out this figure, satisfying the fact that Ad and Ac are both straight lines. you find the ultimately  it forms a right-angled triangle with sides AC and AD and hypotenuse CD.

Now, you may use Pythagoras theorem to solve:

AC^2 + AD^2 = CD^2

12.3^2 + 9.15^2 = CD^2

CD^2 = 235.0125

CD = square root of 235.0125 = 15.33cm

Hope this helps

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3 years ago
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