Isolate the x in both cases. What you do to one side, you do to the other.
11x + 4 < 15
Subtract 4 from both sides
11x + 4 (-4) < 15 (-4)
11x < 11
isolate the x, divide 11 from both sides
11x/11 < 11/11
x< 1
x < 1 is your answer for the first one
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Again, isolate the x.
12x - 7 > -25
Add 7 to both sides
12x - 7 (+7) > -25 (+7)
12x > -18
Isolate the x, divide 12 from both sides
12x/12 > -18/12
x > -1.5 is your answer for the second one.
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hope this helps
Answer:
Let d be the remaining distance.
Let t be the remaining time.
The standard distance equation is:
d = rt
We are given the rate as 2, so:
d = 2t
At the start of the walk, the remaining distance is 3 miles.
The remaining time is 1.5 hours.
At the end of the walk, the remaining distance is 0 miles.
The remaining time is 0 hours.
A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.
Answer:
The graph of this would be a solid line
Answer:
option 4.
16 square units
Step-by-step explanation:
as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.
P = (2 , 4)
S = (4 , 2)
we have to subtract the values of p from s
PS = (4 - 2 , 2 - 4)
PS = (2 , -2)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
PS^2 = 2^2 + -2^2
PS = √ 4 + 4
PS = √8
PS = 2√2
S = (4 , 2)
R = (8 , 6)
SR = (8-4 , 6-2)
SR = (4 , 4)
by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2
h: hypotenuse
c1: leg 1
c2: leg 2
SR^2 = 4^2 + 4^2
SR = √ (16 + 16)
SR = √32
SR = 4√2
having the values of 2 of its sides we multiply them and obtain their area
PS * RS = Area
2√2 * 4√2 =
16
Answer:
The scale factor will be 0.25 and the length of the side will be 8.75 cm. Hope it helps :)
Step-by-step explanation:
Answer:
63%
Step-by-step explanation:
total balances/total credit limit
(675.49+902.43)/(1500+1000)