Answer:
A) g is increasing, and the graph of g is concave up.
Step-by-step explanation:
g'(x) = ∫₀ˣ e^(-t³) dt
Since e^(-t³) is always positive, ∫₀ˣ e^(-t³) dt is positive when x > 0. So the function is increasing.
Find g"(x) by taking the derivative using second fundamental theorem of calculus:
g"(x) = e^(-x³)
g"(x) is always positive, so the function is always concave up.
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1/2*1/3 = 1/6
1/6 is already in its simplest form.
