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inessss [21]
3 years ago
6

What increases the concentration of OH ions

Chemistry
1 answer:
Sliva [168]3 years ago
6 0

Answer:

Explanation: By adding base to a solution increases concentration of OH ions.

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Find the volume of an object that has a density of 3.14 g/mL and a mass of 52.9 g.
Natasha_Volkova [10]

Answer:

The answer is

<h2>16.8 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of object = 52.9 g

density = 3.14 g/mL

The volume of the object is

volume =  \frac{52.9}{3.14}  \\   = 16.847133757...

We have the final answer as

<h3>16.8 mL</h3>

Hope this helps you

5 0
3 years ago
Which of the following is true for balancing equations? A. The number of products should be equal to the number of reactants. B.
AlexFokin [52]

D.) There must be an equal number of atoms of each element on both sides of the equation

5 0
3 years ago
Read 2 more answers
The Percentage of salt-water vs. fresh-water:???%
I am Lyosha [343]

Answer:

<em><u>Over 96 percent is saline. Of total freshwater, over 68 percent is locked up in ice and glaciers. Another 30 percent of freshwater is in the ground.</u></em>

6 0
2 years ago
Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?
Sindrei [870]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂   = 4 x 1 / 2

= 2  moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x  2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!
8 0
3 years ago
Given the standard heats of reaction
ANTONII [103]

Answer:

Explanation:

M(s) → M (g ) + 20.1 kJ --- ( 1 )

X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )

M( s) + 2 X₂(g) → M X₄ (g ) - 98.7 kJ ----- ( 3 )

( 3 ) - 2 x ( 2 ) - ( 1 )

M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s)  → M X₄ (g ) - 98.7 kJ -  2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ

0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ

4 X (g ) +  M (g ) =  M X₄ (g ) - 773.4kJ

heat of formation of M X₄ (g ) is - 773.4 kJ

Bond energy of one M - X bond =  773.4 / 4 =  193.4 kJ / mole

6 0
3 years ago
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