Answer:
NBr₃ is the excess reactant.
Explanation:
- 2NBr₃ + 3NaOH → N₂ + 3NaBr + 3HOBr
We can solve this problem by <u>calculating how many moles of NaOH would react completely with 40 moles of NBr₃</u>, using the <em>stoichiometric coefficients </em>of the reaction:
- 40 mol NBr₃ *
=60 moles NaOH
As the required number of NaOH moles is higher than the available number (60 required vs 48 available), NaOH is the limiting reactant.
As such, the excess reactant is NBr₃.
For every 2 moles of CO and 1 mole of O2, 2 moles of CO2 will be produced.
The ratio is 2:1:2.
Hope this helps! :)
Answer:
C. Combustion
Explanation:
Combustion- an organic compound containing carbon, hydrogen and sometimes oxygen reacts with oxygen gas to form carbon dioxide and water.
The correct answer is C. Colligative properties only depend upon the number of solute particles in a solution but not on the identity or nature of the solute and solvent particles. I hope this anwers your question.
the compound with the smaller lattice energy is potassium sulphide here the size of the molecule play a important role
The quantity of energy released by the electrostatic attraction of oppositely charged ions is known as lattice energy (L.E). The ion's size and charge affect the lattice energy.
lattice energy is inversely proportional to size of ion and directly proportional to charge of the ion. They are each charged equally that is plus two and minus two However, because the Sulphur is larger in size and the oxygen is lesser in this case, The lattice energy of potassium oxide is larger the lattice energy of potassium sulphide is smaller.
To learn more about lattice energy :
brainly.com/question/18222315
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