Question

A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each solution should be used if 28 28 gallons of the 18 % 18% solution are needed?

Answer 1

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ = concentration of ist disinfectant solution = 16 %

$V_1$ = volume of pure acid solution = x gallons

$C_2$ = concentration of another disinfectant solution= 23%

$V_2$ = volume of another acid solution= (28-x) gallons

$C_3$ = concentration of resulting disinfectant solution = 18 %

$V_1$ = volume of resulting acid solution = 28 gallons

$16\times x+23\times (28-x)=18\times 28$

$x=20galllons$

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.