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Olenka [21]
3 years ago
13

A mixture of 18 % 18% disinfectant solution is to be made from 16 % 16% and 23 % 23% disinfectant solutions. How much of each so

lution should be used if 28 28 gallons of the 18 % 18% solution are needed?
Chemistry
1 answer:
jeka943 years ago
7 0

Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

Explanation:

According to the dilution law,

C_1V_1+C_2V_2=C_3V_3

where,

C_1 = concentration of ist disinfectant solution = 16 %

V_1 = volume of pure acid solution = x gallons

C_2 = concentration of another disinfectant solution= 23%

V_2 = volume of another acid solution= (28-x) gallons

C_3 = concentration of resulting disinfectant solution = 18 %

V_1 = volume of resulting acid solution = 28 gallons

16\times x+23\times (28-x)=18\times 28

x=20galllons

(28-x) = (28-20) = 8 gallons

Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.

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