Charles law states that at constant pressure, a given quantity of gas will have a volume proportional to the absolute temperature.
Explanation:
Therefore, a plot of volume versus absolute temperature should yield a straight line. And indeed it does. Real gases liquefy before absolute zero is reached, however, the value
0
K
may be extrapolated on a graph.
Answer:
1)
a) 3.9 mol.
b) The limiting reactant here is HBr that is in a low no. of moles and Al is in excess.
2)
a) 5.45 mol.
b) The limiting reactant here is Si that is in a low no. of moles and N2 is in excess.
3)
a) 2.36 mol.
b) The limiting reactant here is KI that is in a low no. of moles and CuCl2 is in excess.
4)
a) 2.36 mol.
b) The limiting reactant here is O2 that is in a low no. of moles and FeS2 is in excess.
5)
a) 13.24 mol.
b) The limiting reactant here is NH3 that is in a low no. of moles and NO is in excess.
6)
a) 2.71 mol.
b) The limiting reactant here is O2 that is in a low no. of moles and C2H6 is in excess.
7)
a) 7.085 mol.
b) The limiting reactant here is NaOH that is in a low no. of moles and As is in excess.
8)
a) 5.632 mol.
b) The limiting reactant here is H2 that is in a low no. of moles and Au2S3 is in excess.
9)
a) 5.6625 mol.
b) The limiting reactant here is H2O that is in a low no. of moles and CO2 is in excess.
10)
a) 7.905 mol.
b) The limiting reactant here is Fe that is in a low no. of moles and O2 is in excess.
Explanation:
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Answer:
The second option
Explanation:
The process of elimiation.
1. We know liquids dont have a definite shape, they will morph into whatever enviroment theyre in
3. Solids dont expand based on what container theyre in, they either dont fit or they do
4. We know that liquid expands, so we can also rule this one out.
Which leaves us with option 2 to be correct.
Answer:
<em>Solution:</em>
Explanation:
V1 = 3.00m3
T1 = 150kPa
V2 = 1.20m3
T2 = x
As ,
<u> V1 </u> = <u>V2</u>
T1 T2
<u> 3.00</u> = <u>1.20</u>
150 X
3.00 x X = 150 x 1.20
3.00X = 180
X = <u>180</u>
3.00
<em>X = 60 kPa</em>