Boron would have the lower first ionization energy.
Be: 1s2 2s2
B: 1s2 2s2 2p1 -> electron from the p orbital is easier to eject than than electron from the s orbital.
If nitrogen monoxide (NO) is added to 2SO2(g) + O2(g) → 2SO3(g),
it will react with O2 and decrease the reaction rate by lowering the amount of O2. So the answer is C. NO decreases collisions between the SO2 and O2 molecules.
Answer:
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