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Alexxx [7]
3 years ago
8

Draw the major organic product of the regioselective reaction of 2-methyl-2-pentene with H2O in presence of H2SO4. You do not ha

ve to consider stereochemistry. You do not have to explicitly draw H atoms. In your answer, draw the expanded structure for the acetyl group (Ac). Do not include lone pairs in your answer. They will not be considered in the grading.

Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

2-methyl-2-pentanol is produced as a major product

Explanation:

  • Double bond in 2-methyl-2-pentene is protonated first by consuming a proton from H_{2}SO_{4}.
  • A carbocation intermediate is formed after protonation of double bond. Most stable carbocation is formed as a major intermediate.
  • Here a tertiary carbocation is formed as a major intermediate.
  • H_{2}O gives subsequent nucleophilic addition to the carbocation intermediate and produce 2-methyl-2-pentanol as a major product.
  • Reaction mechanism and major organic product has been shown below.

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3 years ago
Which element has a larger atomic radius than sulfur? chlorine cadmium fluorine oxygen
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  • <u>Cadmium has larger atomic radius than sulfur.</u>

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

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  • Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

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  • O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

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