1 source would be fossil fuels
The second would be decomposition
Answer:
a) atoms Pb = 4.3595 E22 amu
b) g = ( 6.022 E23 amu ) × ( Mw )
Explanation:
sample:
∴ m = 15.00 g
a) atoms Pb = ?
⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)
⇒ atoms Pb = 4.3595 E22 amu
b) relationship:
∴ 1 mol (n) ≡ 6.022 E23 amu......(1)
∴ mass (g) ≡ (Mw)×(n)
⇒ n = g / Mw..........(2)
∴ Mw: molecular weight
(1) = (2):
⇒ g / Mw ≡ 6.022 E23 amu
⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )
Answer:
Sharing of electrons such that each atom attains an octet
Answer:
The answer to your question is 1.25 M
Explanation:
Data
Molarity 1 = ?
Volume 1 = 60 ml
Molarity 2 = 0.5 M
Volume 2 = 150 ml
Process
1.- Write the dilution formula
Molarity 1 x Volume 1 = Molarity 2 x Volume 2
-Solve for Molarity 1
Molarity 1 = Molarity 2 x Volume 2 / Volume 1
-Substitution
Molarity 1 = (0.5)(150) / 60
-Simplification
Molarity = 75 / 60
-Result
Molarity = 1.25 M
Answer:
The answer is 0.36 kg/s NO
Explanation:
the chemical reaction of NH3 to NO is as follows:
4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)
We have the following data:
O2 Volume rate = 645 L/s
P = 0.88 atm
T = 195°C + 273 = 468 K
NO molecular weight = 30.01 g/mol
we calculate the moles found in 645 L of O2:
P*V = n*R*T
n = P*V/R*T
n= (0.88 atm * 645L/s)/((0.08205 L*atm/K*mol) * 468 K) = 14.78 moles of O2
With the reaction we can calculate the number of moles of NO and with its molecular weight we will have the rate of NO:
14.78 moles/s O2 * 4 molesNO/5 molesO2 * 30.01 g NO/1 molNO x 1 kgNO/1000 gNO = 0.36 kg/s NO