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Alexxx [7]
3 years ago
8

Draw the major organic product of the regioselective reaction of 2-methyl-2-pentene with H2O in presence of H2SO4. You do not ha

ve to consider stereochemistry. You do not have to explicitly draw H atoms. In your answer, draw the expanded structure for the acetyl group (Ac). Do not include lone pairs in your answer. They will not be considered in the grading.

Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

2-methyl-2-pentanol is produced as a major product

Explanation:

  • Double bond in 2-methyl-2-pentene is protonated first by consuming a proton from H_{2}SO_{4}.
  • A carbocation intermediate is formed after protonation of double bond. Most stable carbocation is formed as a major intermediate.
  • Here a tertiary carbocation is formed as a major intermediate.
  • H_{2}O gives subsequent nucleophilic addition to the carbocation intermediate and produce 2-methyl-2-pentanol as a major product.
  • Reaction mechanism and major organic product has been shown below.

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antiseptic1488 [7]

Here's link to the answer:

tinyurl.com/wpazsebu

4 0
2 years ago
A dark brown binary compound contains oxygen and a metal. It is 13.38% oxygen by mass. Heating it moderately drives off some of
Leto [7]

Answer:

a) Mass of O in compound A = 32.72 g

Mass of O in compound B =  21.26 g

Mass of O in compound C = 15.94 g

b) Compound A = MO2

Compound B = M3O4

Compound C = MO

c) M = Pb

Explanation:

Step 1: Data given

A binairy compound contains oxygen (O) and metal (M)

⇒ 13.38 % O

⇒ 100 - 13.38 = 86.62 % M

After heating we get another binairy compound

⇒ 9.334 % O

⇒ 100 - 9.334 = 90.666 % M

After heating we get another binairy compound

⇒ 7.168 % O

⇒ 100 - 7.168 = 92.832 % M

The first compound has an empirical formula of MO2

⇒ 1 mol M for 2 moles O

Step 2: Calculate amount of metal and oxygen in each

compound A:   M  = m1 *0.8662    O = m1 *0.1338

compound B:   M  = m2 *0.90666    O = m2 *0.09334

compound C:   M  = m3 *0.92832    O = m3 *0.07168

Step 3: Calculate mass of oxygen with 1.000 grams of M

Compound A: 1.000g * 0.1338 m1gO  / 0.8662m1gMetal = 0.1545

Compound B: 1.000g * 0.09334 m2gO  / 0.90666m2gMetal = 0.1029

Compound C: 1.000g * 0.07168 m3gO  / 0.92832m3gMetal = 0.07721

Step 4:

1 mol MO2 has 1 mol M and 2 moles O

m1 = (mol O * 16)/0.1338   m1 = 239.2 grams

1 mol M = 0.8632*239.2 = 206.48

0.90666m2 = 206.48  ⇒ m2 = 227.74 g

0.92832m3 = 206.48  ⇒ m3 = 222.42 g

Step 5: Calculate mass of O

Mass of O in compound A = 239.2 - 206.48 = 32.72 g

Mass of O in compound B = 227.74 - 206.48 = 21.26 g

Mass of O in compound C = 222.42- 206.48 = 15.94 g

Step 6: Calculate moles

Moles of O in compound A ≈ 2

⇒ MO2

Moles of O in compound B = 21.26 / 16 ≈ 1.33

⇒ M3O4

Moles of O compound C = 15.94 /16 ≈ 1 moles

⇒ MO

Step 7: Calculate molar mass

The mass of 1 mol metal is 206.48 grams  ⇒ molar mass ≈ 206.48 g/mol

The closest metal to this molar mass is lead (Pb)

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3 years ago
Is all air pollution caused by humans
larisa86 [58]
Well partly yes because air pollution can happen when we burn fossil fuels, it can happen when we use vehicles and household/farming chemicals can cause air pollution so yes it is caused by humans
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3 years ago
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I KNOW THE ANS JUST NEED AN EXPLANATION...PLEASE I WILL Mark you the brainiest
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I’m pretty sure it would be D.
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How many oxygen molecules are produced when 3.2×1022 molecules of water decompose?
snow_lady [41]
What this is confusing
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