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Alexxx [7]
3 years ago
8

Draw the major organic product of the regioselective reaction of 2-methyl-2-pentene with H2O in presence of H2SO4. You do not ha

ve to consider stereochemistry. You do not have to explicitly draw H atoms. In your answer, draw the expanded structure for the acetyl group (Ac). Do not include lone pairs in your answer. They will not be considered in the grading.

Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

2-methyl-2-pentanol is produced as a major product

Explanation:

  • Double bond in 2-methyl-2-pentene is protonated first by consuming a proton from H_{2}SO_{4}.
  • A carbocation intermediate is formed after protonation of double bond. Most stable carbocation is formed as a major intermediate.
  • Here a tertiary carbocation is formed as a major intermediate.
  • H_{2}O gives subsequent nucleophilic addition to the carbocation intermediate and produce 2-methyl-2-pentanol as a major product.
  • Reaction mechanism and major organic product has been shown below.

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What are two sources of carbon dioxide
jonny [76]
1 source would be fossil fuels
The second would be decomposition
7 0
3 years ago
20. The mass of one mole of lead (Pb) atoms is 207.2 g. Use a proportion to calculate the n
AnnZ [28]

Answer:

a) atoms Pb = 4.3595 E22 amu

b) g = ( 6.022 E23 amu ) × ( Mw )

Explanation:

  • m Pb = 207.2 g / mol Pb

sample:

∴ m = 15.00 g

a) atoms Pb = ?

  • 1 mol ≡ 6.022 E23 amu

⇒ atoms Pb = (15.00g Pb)(mol Pb/207.2 g)(6.022 E23 amu/mol)

⇒ atoms Pb = 4.3595 E22 amu

b) relationship:

∴ 1 mol (n) ≡ 6.022 E23 amu......(1)

∴ mass (g) ≡ (Mw)×(n)

⇒ n = g / Mw..........(2)

∴ Mw: molecular weight

(1) = (2):

⇒ g / Mw ≡ 6.022 E23 amu

⇒ g ≡ ( 6.022 E23 amu ) × ( Mw )

8 0
3 years ago
Covalent bonds form through:
Annette [7]

Answer:

Sharing of electrons such that each atom attains an octet

4 0
2 years ago
What is the molarity of a stock solution if 60 mL were used to make 150 mL of a .5M solution
kirza4 [7]

Answer:

The answer to your question is 1.25 M

Explanation:

Data

Molarity 1 = ?

Volume 1 = 60 ml

Molarity 2 = 0.5 M

Volume 2 = 150 ml

Process

1.- Write the dilution formula

       Molarity 1 x Volume 1 = Molarity 2 x Volume 2

-Solve for Molarity 1

       Molarity 1 = Molarity 2 x Volume 2 / Volume 1

-Substitution

        Molarity 1 = (0.5)(150) / 60

-Simplification

        Molarity = 75 / 60

-Result

        Molarity = 1.25 M

6 0
3 years ago
Nitric acid is a key industrial chemical, largely used to make fertilizers and explosives. The first step in its synthesis is th
Hunter-Best [27]

Answer:

The answer is 0.36 kg/s NO

Explanation:

the chemical reaction of NH3 to NO is as follows:

4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)

We have the following data:

O2 Volume rate = 645 L/s

P = 0.88 atm

T = 195°C + 273 = 468 K

NO molecular weight = 30.01 g/mol  

we calculate the moles found in 645 L of O2:

P*V = n*R*T

n = P*V/R*T

n= (0.88 atm * 645L/s)/((0.08205 L*atm/K*mol) * 468 K) = 14.78 moles of O2

With the reaction we can calculate the number of moles of NO and with its molecular weight we will have the rate of NO:

14.78 moles/s O2 * 4 molesNO/5 molesO2 * 30.01 g NO/1 molNO x 1 kgNO/1000 gNO = 0.36 kg/s NO

8 0
3 years ago
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