All categories

2 years ago

You need to measure out exactly 6.7 mL of water for an experiment. Which of the following would be the best tool for the job?

Chemistry

2 answers:

Free_Kalibri [48]2 years ago

4 0

The answer will be 10mL graduated cylinder

Zepler [3.9K]2 years ago

3 0

Answer:

The answer for this problem would be "b. A 10 mL graduated cylinder".

Explanation:

The reason for this is because with a instrument that is closer to the value you're trying to measure, the more precise it will be.

For example using a teaspoon to measure something rather than a cup.

You might be interested in

When an atom gains an electron,what charge does the ion have

irakobra [83]

Answer:

if an atom gains an electron, the ion has negetive charge

7 0

3 years ago

Calculate the moles of 36.030 g of H2O.

lions [1.4K]

Answer: 1.99 mol h20

Explanation:

you have 36.030 g, trying to get it into mols

to get from g to mols, use the molar mass (periodic table)

36.030 g h20 (1 mol/18.02g) = 1.99 mol h20

4 0

3 years ago

What does the 3 indicate in 1s22s22p63s1?

Dahasolnce [82]

The 3 indicates the third electron shell. (Which has only 1 electron in it in this configuration)

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

What are other portals of entry besides needlesticks?

aivan3 [116]

Answer:

Inhalation (via the respiratory tract)Absorption (via mucous membranes such as the eyes) Ingestion (via the gastrointestinal tract)

Explanation:

The opening where an infectious disease enters the host's body such as mucus membranes, open wounds, or tubes inserted in body cavities like urinary catheters or feeding tubes.

6 0

2 years ago

By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm

kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

$\tt 0.943~L=0.943\times 10^{-3}m^3$

Volume of oil dumped = volume of swimming pool

$\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}$

3 0

3 years ago