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seropon [69]
4 years ago
8

(a) 4.64 x 1024 atoms Bi into grams

Chemistry
1 answer:
nexus9112 [7]4 years ago
5 0

Answer:

1610.7 g is the weigh for 4.64×10²⁴ atoms of Bi

Explanation:

Let's do the required conversions:

1 mol of atoms has 6.02×10²³ atoms

Bi → 1 mol of bismuth weighs 208.98 grams

Let's do the rules of three:

6.02×10²³ atoms are the amount of 1 mol of Bi

4.64×10²⁴ atoms are contained in (4.64×10²⁴ . 1) /6.02×10²³ = 7.71 moles

1 mol of Bi weighs 208.98 g

7.71 moles of Bi must weigh (7.71 . 208.98 ) /1 = 1610.7 g

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3 years ago
Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)
elena-s [515]

Answer:  a) Sodium and nitrogen : NaN_3  : sodium nitride.

b) Oxygen and strontium : SrO :  strontium oxide.

c) Aluminum and chlorine : AlCl_3  : aluminium chloride.

d) Cesium and bromine : CsBr  : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as Na^{+} cation and nitrogen forms an anion N^{3-} with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaN_3  named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as Sr^{+} cation and oxygen forms an anion O^{2-} with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral SrO  named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as Al^{3+} cation and chlorine forms an anion Cl^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral AlCl_3  named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as Cs^{+} cation and bromine forms an anion Br^{-} with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral CsBr  named as cesium bromide.

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3 years ago
What is a small description of a molecule
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Answer:

molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

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What do liver cells do?
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4 0
4 years ago
Compare the models of the superconductor to the CaTiO3 models. What similarities and differences do you notice? How do the coord
bulgar [2K]

Answer:

Compare the models of the superconductor to the CaTiO3 models.

What similarities and differences do you notice?

The differences are in the crystal structure unit cell, consisting of five atoms  with calcium atoms at the corners, a titanium atom at the center and oxygen at centers forming an octahedron, and the similarities are in the HTSC cuprates structures.

How do the coordination numbers of the central ions compare?

The Ca+2 cation layers are insulating and donate electrons to the CuO2 planes. The Sro layers are barriers, isolate groups of CuO2 planes from each other, the ca2 and bi2 are charge reservoir layers.

Explanation:

Allow the current to flow without resistence or interruption, through a superconductor material at room temperature, is still a not fullfilled dream in the superconductivity research.

Transition temperatures (Tc) achieving though, have opened the options for many applications, high temperature superconductors are now the main researchs´ focusing, known as perovskites, which are simply ceramics, such as yttrium barium copper oxides (YBCOs) or 1-2-3 compounds and the bismuth strontium calcium copper oxide (BSCCOs) or Pb-BSCO (PBSCCO) are the best insulators known at room temperature, and at liquid nitrogen temperature, the become perfectly superconducting.

The discovery of superconducting transition at 35 K in lanthanum barium copper oxide ceramic system- La2-xBaxCuO4 and the 92 K for 123 systems made a difference among them as these systems contained rare-earth elements.

A great step was gained with the discovery of the first high temperature (Tc) oxide ceramic system, based on Bi-Sr-Cu-O perovskite, which did not have any rare-earth component, followed by several discoveries of these rare-earth free systems, such as the Bi-Sr-Cu-O, which increased Tc to 85 K adding calcium, Br-Sr-Ca-Cu-O system which reached 110 K; Ti-Ba-Ca-Cu-O system which reached a Tc of 125 K, but the Bi systems synthesis and rare-earth systems as YBCO differ in simplicity and getting a monophase superconducting phase is still not fullfilled.

Varying elemental ratios and dopants such as Pb, and so forth has given only partial success, even the Bi compositions which showed to have monophase in Bi systems, reproducibility controlling elemental ratios cause a high percentage of inaccuracy.

In comparisson with the conventional solidstate sintering technique, the glassy precursor route is more efficient and realizable to achieving superconducting monophase with rareearth free BSCCO perovskites or Bi perovskites, with interesting parameters and optimizing factors.

YBCO gave the highest Tc ever in 1987, easy to synthesize and good phase stability, bismuth-based cuprates gave a Tc of 110 Kc, Thalium-based cuprates gave a Tc of 120 to 125 K and mercury-based cuprates that gets a Tc of 135 K, which created a new hope for HTSC based on cuprates.

Most of the known cuprate superconductors belong to a single structural familiy closely realted to each other.

Bistmuth-based cuprates are good HTSC as their grain alignment is along the c-axis, which increases the critical current.

Bi-Sr-Ca-Cu-O

   

8 0
4 years ago
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