So to put them in intervals of 5 you would have:
70-74
75-79
80-84
85-89
90-94
95-99
In these intervals you would have:
70-74: 72
75-79: 78
80-84: 81
85-89: 86, 86, 87
90-94: 92, 92, 92
95-99: 98
The second interval is 75-79 where there is only one number. Therefore the frequency will be 1.
The correct answer is A. Hope this helps! :)
3/10 <7/8
Please my answer
A Hi complete the table shown with an expression need to solve the problem and solve in
<h2>
Forming Equations from Word Problems</h2>
To form equations from word problems, we can derive mathematical operations as well as variables from the given information.
In this case, each time Walker reads a certain number of pages, we subtract that from the total number of pages left to know how many pages is left to read.
<h2>Solving the Question</h2>
<em>Let r represent the pages left to read.</em>
<em />
792 pages in total
Walker reads 15 pages a day during the week and 25 pages a day during the weekend.
- There are 5 weekdays, and he reads 15 pages each of those days. ⇒ <em>r</em> = 792 - 5×15
- There are 2 weekend days, and he reads 25 pages each of those days.
⇒ <em>r</em> = 792 - (5×15 + 2×25)
5 weeks have passed
- Multiply the terms representing the number of pages he reads a week by 5, for 5 weeks.
⇒ <em>r</em> = 792 - (5×15 + 2×25)×5
<h2>Answer</h2>
<em>r</em> = 792 - (5×15 + 2×25)×5
Answer:
The measure of arc a is 86°
Step-by-step explanation:
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
so
86°=(1/2)[arc c+arc a]
see the attached figure with letters to better understand the problem
In this problem
Triangles ABO and CDO are congruent by SSS postulate theorem
∠AOB=∠COD
∠AOB=arc a -----> by central angle
∠COD=arc c -----> by central angle
therefore
The measure of arc a is congruent with the measure of arc c
arc a=arc c
so
86°=(1/2)[2arc a]
86°=[arc a]
arc a=86°
