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kvv77 [185]
3 years ago
9

What is the square root of 3/2 in fraction form?

Mathematics
1 answer:
V125BC [204]3 years ago
3 0
The answer is square root 6/2
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A label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. What is the lateral surface area of the label of the
Soloha48 [4]

Answer:

52\pi \text{ cm}^2\approx 162.11\text{ cm}^2

Step-by-step explanation:

We have been given that a label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. We are asked to find the lateral surface area of the label of the soup can in square centimeters.

We will use lateral surface area of cylinder to solve our given problem as:

LA=2\pi rh, where,

r = Radius of cylinder,

h = height of cylinder.

Upon substituting our given values in above formula, we will get:

LA=2\pi \times\text{4.3 cm}\times \text{6 cm}

LA=51.6\pi \text{ cm}^2

LA=162.10618\text{ cm}^2

Therefore, the lateral surface area of the label of the soup is approximately 162.11 square cm.

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3 years ago
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Bogdan [553]
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ziro4ka [17]
Ha. That looks alot like i-ready. (i-ready sucks butt.)

But the horror that is i-ready aside, your answer is the third one : The proportion of grandparents that feel safe entering their account information online is 0.32.

32% converted to a decimal is 0.32, and 68% converted to a decimal is 0.68. That would mean that the proportion for grandparents that feel safe doing so is 0.32, and the number of grandparents that don't feel safe doing so is 0.68.
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The question that is asked
Vika [28.1K]

Answer:

the answer is 35.0° pls thank :)

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3 years ago
if f is a differentiable function and f(0)=-1 and f(4)-3 then which of the following must be true there exists a c in [0,4] wher
iragen [17]

Answer:

True, see proof below.

Step-by-step explanation:

Remember two theorems about continuity:

  1. If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
  2. (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.

If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.

7 0
3 years ago
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