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3 years ago

6

6. Your 60-watt light bulb is plugged into a 110-volt household outlet and left on for 3 hours. The utility company charges you

$0.11 per kiloWatt•hr. Calculate the cost of such a mistake

2 answers:

Crank3 years ago

7 0

Answer:

$0.0198

Explanation:

Commercial power is consumed in kilowatt-hours (kWh).

kWh is the energy supplied by a rate of working of 1000 W in 1 hours.

Most utility company sells electric energy in units of kWh

From the question,

Total energy consumed by the light bulb when for 3 hours = (60×3/1000) kWh = 0.18 kWh.

If the utility company charges $0.11 for 1 kWh.

I.e,

1 kWh = $0.11

Then, 0.18 kWh = 0.11(0.18) = $0.0198

Hence the cost of such mistake is = $0.0198

elena55 [62]3 years ago

6 0

Answer:

0.0198 dollars

Explanation:

We first obtain the total energy drawn by the light bulb in kilowatt-hour (kW-hr) using the following relationship;

Energy = power rating x time

Given;

power rating = 60W,

time = 3hrs

Therefore,

Energy consumed = 60W x 3hr

Energy consumed = 180W-hr = 0.18kW-hr

We then multiply this energy in kW-hr by he amount charged per unit kW-hr as follows;

Given that 1kW-hr= 0.11 dollars

0.18kW-hr = 0.18 x 0.11

= 0.0198 dollars

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Answer:

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Explanation:

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So once we got the free body diagram, we can analyze it and build our sum of forces in the x and y directions. Notice that according to the diagram, there are 4 forces to this problem, Normal (N), Weight (W), kinetic friction (fk) and the 750N force.

As one may see in the free body diagram, two of the forces are vertical forces: N and W, so we can use them to build a sum of forces:

Starting with the sum of forces in the y-direction, we get:

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We set the sum equal to zero because there is no movement in the y-direction, so the system is in vertical equilibrium.

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$f_{k}=2450N*0.12$

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In this case the sum is equal to mass times acceleration because the crate is moving horizontally due to the action of a force, so it will have an acceleration.

so the sum of forces look like this:

750N- $f_{k}$ =ma

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when solving for a we get:

$a=\frac{759N-294N}{250kg}\\ \\a=1.8m/s^{2}$

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A train travels due north in a straight line with a constant speed of 100 m/s. Another train leaves a station 2,881 m away trave

damaskus [11]

Answer:

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From the question, Train B leaves a station 2,881 m away (that is 2,881 m away from Train A position).

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At the position where the trains will collide, the two trains must have traveled for equal time, t.

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$Velocity = \frac{Distance }{Time }\\$

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$\frac{x}{100} = \frac{2881 - x}{136}$

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Hence, Train B would have covered (2881 - 1221)m = 1660 m

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