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Lostsunrise [7]
3 years ago
7

Can someone help me with this please

Mathematics
2 answers:
svp [43]3 years ago
5 0
I got it right it is 63.6
Pepsi [2]3 years ago
3 0

Answer:

63.6

Step-by-step explanation:

\sqrt{45^{2} + 45^{2}} = \sqrt{4050}

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Mr. Claw received a job with an annual salary of $51,000. He will receive a 1.5% increase every year. How much will Mr. Claw's s
NeX [460]

Answer: $53,330

Step-by-step explanation:

This is an exponential function so to find the salary in 3 years, you need to use a future value formula such as :

= Amount * ( 1 + rate) ^ number of years

Amount = $51,000

Rate = 1.5%

Number of years = 3 years

Salary = 51,000 * ( 1 + 1.5%)³

= 53,329.59

= $53,330

3 0
3 years ago
6TH GRADE MATH I WILL GIVE BRAINLIEST HELP ASAP
dimaraw [331]

Answer:

Point D and It is equivalent to 75%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Guys please help i'm stup!d
Nataly [62]

Answer:

Option B: 0.4

Step-by-step explanation:

We have 20 dots.

Such that each column represents the repetitions for each proportion.

So:

0.1 -> 3 times

0.2 -> 1 time

0.3 -> 4 times

0.4 -> 6 times

0.5 -> 3 times

0.6 -> 3 times

Now we can compute the mean of these values, and that will be the best estimation we can make with the given data.

Remember that for a set of N values:

{x₁, x₂, ..., xₙ}

The mean is:

M = \frac{x_1 + x_2 + ... + x_n}{N}

In this case we have the set of 20 points described above, then the mean is:

M = \frac{3*0.1 + 1*0.2 + 4*0.3 + 6*0.4 + 3*0.5 + 3*0.6}{20} = 0.37

Rounding to the first place after the decimal point, we get:

M = 0.4

Then the correct option is option B.

5 0
3 years ago
Cholesterol levels for a group of women aged 30-39 follow an approximately normal distribution with mean 190.14 milligrams per d
Anettt [7]

Answer:

Step-by-step explanation:

Hello!

X: Cholesterol level of a woman aged 30-39. (mg/dl)

This variable has an approximately normal distribution with mean μ= 190.14 mg/dl

1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:

P(Z≥z₀)= 0.093

-*or*-

P(Z≤z₀)= 0.907

Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:

P(Z≤z₀)= 0.907

Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:

z₀= 1.323

2.

Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:

Z= (X- μ)/δ ~N(0;1)

Z= (X- μ)/δ

Z*δ= X- μ

δ=(X- μ)/Z

δ=(240-190.14)/1.323

δ= 37.687 ≅ 37.7 mg/dl

I hope it helps!

8 0
3 years ago
Suri makes $15 per hour and gets a weekly bonus of $25. Juan makes $14 per hour and gets a weekly bonus of $50. Is it possible f
Papessa [141]

Answer:

Yes. Suri and Juan can make the same amount of wages by working 25 hours in one week.

Step-by-step explanation:

Let each of them work x hours per week.

Suri makes $15 per hour, so in x hours Suri will make $ 15x. The total wages per week for Suri will be:

Total Wages = y = 15x + Bonus = 15x + 25

Juan makes $14 per hour, so in x hours Juan will make $ 14x. The total wages per week for Juan will be:

Total Wages = y = 14x + Bonus = 14x + 50

If they will make the same wages, their wages must be equal, i.e.

15x + 25 = 14x + 50

15x - 14x = 50 - 25

x = 25

This result shows us that if Suri and Juan work for 25 hours per week they will make the same amount of wages.

7 0
3 years ago
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