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luda_lava [24]
3 years ago
11

Explain the difference between quadratic equations with one solution, two solutions, and complex solutions

Mathematics
1 answer:
shusha [124]3 years ago
4 0
Recall that given the equation of the second degree (or quadratic)
 ax ^ 2 + bx + c
 Its solutions are:
 x = (- b +/- root (b ^ 2-4ac)) / 2a
 discriminating: 
 d = root (b ^ 2-4ac)
 If d> 0, then the two roots are real (the radicand of the formula is positive). 
 If d = 0, then the root of the formula is 0 and, therefore, there is only one solution that is real and of multiplicity 2 (it is a double root).
 If d <0, then the two roots are complex and, in addition, one is the conjugate of the other. That is, if one solution is x1 = a + bi, then the other solution is x2 = a-bi (we are assuming that a, b, c are real).
 One solution:
 A cut point with the x axis
 Two solutions:
 Two cutting points with the x axis.
 Complex solutions:
 Does not cut to the x axis
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Six less than six timesa number is 12
vovangra [49]
Six (6) less than (subtraction) six (6) times (multiplication) a number (n) is (=) 12.

6n - 6 = 12  

To solve, add 6 to both sides

6n = 18   Dviide both sides by 6
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8. The total weight of a vase and its packaging is: 4 lb. 7 oz. The vase by itself
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Answer:

E

Step-by-step explanation:

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3 years ago
Improper fraction for 3 1/14
TEA [102]

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5 0
4 years ago
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Factor out the GCF from the polynomial.<br> 18x^6+ 81x^5 - 63x^2 +45
kramer

Answer:

The GCF is 9

Step-by-step explanation:

In the given polynomial 18x^6+ 81x^5 - 63x^2 +45  lets represent each term  as its factors

18x^6 = 2 \times 3 \times 3 \times x \times x \times x \times x \times x \times x

81x^5 = 3 \times 3 \times 3 \times  3 \times x \times x \times  x \times  x \times x

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The greatest common factors from each term  are  3 , 3

Thus the GCF =   3 \times 3 = 9

4 0
3 years ago
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