X²/9 + y²/16 = 1
The general for mula of an ellipse is:
(x-h)²/a² + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)
Moreover sin b>a so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].
On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it
Standard Form: ax² + bx + c = y
Basically, you put all the numbers from greatest to least with exponents then variables.
We have the numbers:
9
-x²
2x^5
-7x
Put these numbers from least to greatest from the exponents.
2x^5 - x² - 7x + 9
The degree of the polynomial is the number with the greatest exponent. In this case, the highest exponent is 5.
The degree of the polynomial is 5.
Best of Luck!