Answer:
% change in stopping distance = 7.34 %
Step-by-step explanation:
The stooping distance is given by
We will approximate this distance using the relation
dx = 26 - 25 = 1
T' = 2.5 + x
Therefore
This is the stopping distance at x = 25
Put x = 25 in above equation
2.5 × (25) + 0.5× 
+ 2.5 + 25 = 402.5 ft
Stopping distance at x = 25
T(25) = 2.5 × (25) + 0.5 ×
T(25) = 375 ft
Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft
% change in stopping distance = 
× 100
% change in stopping distance = 7.34 %
Answer:
F(x)=2x^2
Step-by-step explanation:
Basically, a quadratic function has x^2 in it (standard form ax^2+bx+c with non-zero a). The others have x^3, -x, x^4, etc., which clearly are NOT x^2.
Step-by-step explanation:
this creates a right-angled triangle.
the right angle (90°) being the angle between flag pole and ground.
the angle ground-wire is 50°.
because we know that the sum of all angles in a triangle is always 180°, we know then that the angle flagpole-wire is
180 - 90 - 50 = 40°
so, we have the situation to know 1 side and all angles.
to get the other sides we use best the law of sine :
a/sin(A) = b/sin(B) = c/sin(C)
where the sides and related angles are always opposite of each other.
in our case now we have
24/sin(50) = wire/sin(90) = wire/1 = wire = 31.32977494... ft
so, the rounded answer is that the wire must be
31.3 ft long
-6, all of them are the absolute value of 6 or just 6, -6 isn't equivalent to 6.
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<em>Hope this helps :-)</em>
