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Juliette [100K]
3 years ago
13

Are two negative integers postive

Mathematics
2 answers:
garri49 [273]3 years ago
7 0
Two negatives added or multiplied make a positive.
EastWind [94]3 years ago
6 0
Yes,because if you combine two negatives you get a positive
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Graph the quadratic function f(x)= -2x^2-3x+2
schepotkina [342]

Answer:

it would be the graph with the maximum (opening down) in the first photo with the top on the left side of the y axis

4 0
3 years ago
WUTU problems
Tasya [4]

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110

Step-by-step explanation:

Im not sure but the GCF of 10 and 11 should be 110. I hope this helps.

5 0
3 years ago
A soccer ball is kicked in the air off a 22.0 meter high hill. The equation h(t)=-5t^2+10t+22 gives the approximated height h, i
Lana71 [14]

Answer:

Equation: 5t² − 10t + 13 = 0

Answer: No

Step-by-step explanation:

h(t) = -5t² + 10t + 22

When h(t) = 35:

35 = -5t² + 10t + 22

5t² − 10t + 13 = 0

This equation must have at least one real solution if the ball is to reach a height of 35 meters.  Which means the discriminant can't be negative.

b² − 4ac

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The ball does not reach a height of 35 meters.

5 0
3 years ago
Brainliest question Please help me now plz
Novosadov [1.4K]

Answer:

A. Inside the circle

Step-by-step explanation:

K(0, 0), U (6, - 4), V (\sqrt 2,\: 7)

In order to determine whether point V lie inside, outside or on the circle, first we will find the distances between points K & U and then K & V.

KU would be radius of the circle.

  • If KV is smaller than KU, then V will lie inside.
  • If KV is larger than KU, then V will lie outside
  • And If KV = KU, then V will lie ion the circle.

d(KU)  =  \sqrt{ {(6 - 0)}^{2} +  {( - 4 - 0)}^{2}  }  \\  =  \sqrt{ {6}^{2}  +  {( - 4)}^{2} }  \\  =  \sqrt{36 + 16}  \\  \red{ \bold{ d(KU)=  \sqrt{52} }} \\  \\ d(KV)  =  \sqrt{ {( \sqrt{2}  - 0)}^{2} +  {( 7 - 0)}^{2}  }  \\  =  \sqrt{ {( \sqrt{2)} }^{2}  +  {(7)}^{2} }  \\  =  \sqrt{2 + 49}  \\  \purple{ \bold{ d(KV)=  \sqrt{51} }} \\  \\  \because \: d(KU) > d(KV) \\

Hence point V lie inside of the circle.

3 0
3 years ago
Help me please? confused
katen-ka-za [31]

Answer:

see below

Step-by-step explanation:

sqrt(32)

    32

4  *   8

2*2     2*4

         2  * 2*2

Taking pairs

2*2  2*2*2

2 * 2 with one 2 left over

2*2* sqrt(2)

4 sqrt(2)

Woodrow took a group of 3 instead of pairs when taking square roots

5 0
3 years ago
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