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irakobra [83]
3 years ago
15

The graph shows the amount of money paid when purchasing bags of peanuts at the zoo:

Mathematics
1 answer:
abruzzese [7]3 years ago
7 0

Answer:

dive the cost by the number of bags for each dot:

4 / 1 = 4

8 / 2 = 4

12 / 3 = 4

This means each bag cost $4

The equation would be Y = 4X, because you would multiply each bag bought (X) by $4 to get the total cost (Y).

Step-by-step explanation:

BRAINLYIS TPLS

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Sauron [17]
The answer is b. 1/27
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8 0
3 years ago
(-5)x[-8)+1] solving bidmas
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I hope this helps you




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2 years ago
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The probability that a customer's order is not shipped on time is 0.06. A particular customer places three orders, and the order
charle [14.2K]

Answer:

a) There is a 83.06% probability that all orders are shipped on time.

b) There is a 15.90% probability that exactly one order is not shipped ontime.

c) The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

In our problem, there is:

-A 6% probability that a customer's order is not shipped on time.

-A 94% probability that a customer's order is shipped on time.

We have these following orders:

O1 - O2 - O3.

(a) What is the probability that all are shipped on time?

The probabilities that each order is shipped on time are O1 = 0.94, O2 = 0.94 and O3 = 0.94. So:

P = (0.94)^{3} = 0.8306

There is a 83.06% probability that all orders are shipped on time.

(b) What is the probability that exactly one is not shipped ontime?

The order's can be permutated. What this means? It means that we can have O1 late and O2,03 on time, O2 late and O1,O3 on time and O3 late and O1, O2 on time. We have a permutation of 3 elements(the orders) with 2 and 1 repetitions(2 on time and one late).

The probability that an order is late is:

P = (0.94)^{2}(0.06) = 0.053 for each permutation

Considering the permutations:

P = 0.053*p^{3}_{2,1} = 0.053\frac{3!}{2!*1!} = 0.053*3 = 0.1590

There is a 15.90% probability that exactly one order is not shipped ontime.

(c) What is the probability that two or more orders are not shipped on time?

P = P1 + P2, where P1 is the probability that two orders are late and P3 is the probability that all three orders are late.

P1

Considering the permutations, the probability that two orders are late is:

P_{1} = p^{3}_{2,1}*(0.94)*(0.06)^{2} = 3*(0.94)*(0.06)^{2} = 0.0102

There is a 1.02% probability that two orders are late

P2

P_{2} = (0.06)^3 = 0.0002

There is a 0.02% probability that all three orders are late.

The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

5 0
3 years ago
Last summer at camp okey fun okey the ratio of the number of boy campers to the number of girl campers was 8:7 if there were 56
Paraphin [41]
There would be 64 boys, 56/7=8 so you would have to multiple 8 by 8, which equals 64
7 0
3 years ago
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ludmilkaskok [199]

Answer:

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Step-by-step explanation:

Well, the center origin of the circle is given (h,k) =  (-3,5).

Point on the circle is (x,y) = (1,8)

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (-3,5) and (x,y) =  (1,8) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

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(4)^2 + (3)^2 = r^2

16 + 9 = r^2

r^2 = 25

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5 0
2 years ago
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