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olga2289 [7]
3 years ago
9

Find 4 1/5 · 7 2/3. reeeeeeeeeeeee

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

32 1/5 is the answer (32 and 1/5) as a fraction

32.2 is the answer as a decimal.

Step-by-step explanation:

Hope this helps!!

emmainna [20.7K]3 years ago
8 0
The answer is 32.2 in decimal form
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What does 74 divided by 8 equal
Darya [45]
8 goes into 74 nine times but there is a remainder of 2 

9 and a remainder of 2       or        9 and 1/4
8 0
3 years ago
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Which transformation(s) were used to go from the parent graph (red) to the transformed graph (blue)? Check all that apply!
UNO [17]
<h3>2 Answers: </h3><h3>Choice B) Shift down</h3><h3>Choice C) Shift right</h3>

===================================================

Explanation:

Start with the point (-2,-4). Let's try to move it to (2, -9)

To do so, we need to shift down and to the right (in either order).

Specifically we shift 4 units to the right to go from x=-2 to x=4

Note how x=-2 moves to x+4 = -2+4 = 2

Also, we shift 5 units down. We have y = -4 turn into y = -9 as shown below

y ---> y-5 = -4-5 = -9

So the translation rule is (x,y) \to (x+4,y-5)

Let's see what happens when we apply the translation rule to (2,4)

(x,y) \to (x+4, y-5)\\\\(2,4) \to (2+4, 4-5)\\\\(2,4) \to (6, -1)\\\\

which is the other endpoint of the blue segment. This shows that the translation rule works for (2,4) to move to (6,-1)

We do not apply any dilations. The red and blue segments are the same length because translations preserve distance. All we're effectively doing is moving the red segment to land on the blue segment. This means no vertical or horizontal stretches are done. The same can be said about compressions as well.

3 0
3 years ago
A car dealership has found that the length of time before a major repair is required on the new cars it sells is normally distri
weqwewe [10]

Answer:

Step-by-step explanation:

Hello!

The variable of interest in this case is:

X: length of time before a major repair is required on a new car. (months)

This variable has a normal distribution with mean μ= 36 months and a standard deviation σ= 9 months.

If he wants to set a guarantee period in which only 5% of the sold cars fell, the objective is to find the value of X that has below 5% of the cars that need major repairs before the end of the guarantee period.

Check the attachment, the curve represents the distribution of the population of the time it takes before a new car needs major repairs, I've marked approximately where this value of X should be.

Symbolically:

P(X≤a)=0.05

To reach the proper value of "a" you have to work using the standard normal distribution because is a tabulated distribution and you can extrapolate it to any normal distribution.

Z= \frac{X-Mu}{Sigma}~N(0;1)

So the first step is to look in the table of the Z distribution for the value that accumulates 0.05 of probability since it is such a low probability, you have to look for the value in the left side of the table (negative values of Z). You look for 0.05 in the body of the table and then the margins for the corresponding value (see second attachment)

Z_{0.05}= -1.64

Then the value that accumulates 0.05 of probability is -1.64, now you have to reverse the standardization to reach the asked value of X

Z= (a- μ)/σ

(Z*σ)= a - μ

a=(Z*σ)+ μ

a=(-1.64*9)+36

a= 21.24 months.

The guarantee period should be 21.24 months so that only 5% of the sold cars will need major repairs before it wears of.

I hope it helps!

5 0
3 years ago
What value(s) of x will make each equation below true?
kvasek [131]

Answer:

a X=0

b X=0

c X= undetermined

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3 years ago
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What is the equation of the circle?<br> Also no links please
Mnenie [13.5K]

Answer:

(x - 3)^2 + (y + 2)^2 = 2^2.

3 0
3 years ago
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