Answer:
X=6 and Y=3
Step-by-step explanation:
Use SOHCAHTOA, SOH, Sin=Opposite/Hypotenuse, Therefore Sin60°=(3√3)/x ; Xsin60°=3√3 and Sin60° without using 4figuretable or calculator is √3/2, Now x=3√3 ÷√3/2 ;. therefore X=3√3×2/√3= 6. X=6 . Using Pythagoras theorem, 6²={(3√3)² +y²}. Y²= 36-27=9. Y=√9, Y=3. Therefore X=6 and Y=3.
For the area you need the do length x width
Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
The number in the photo should be the answer but the problem might just be that your question was worded incorrectly.
