ANSWER:
X is -5 and 1.
1) cross multiply
2) subtract five from both sides
3) factor
4) check for extraneous
5) ask me if you are still confused.
Answer:
90.
Step-by-step explanation:
We have two lines of code:
y ← x + x + x + x + x
z ← y + y + y
and, x=6 before the execution. Then, when the program starts to run we obtain:
y ← 6 + 6 + 6 + 6 + 6
y ← 30
z ← 30+30+30
z ← 90.
Then, the value of z after excecution is 90.
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
1) (-4,0)lowest and highest x values
2) (2,3)lowest and highest y values
3) (-2,0] point where the graph is going down
5) x-intercept is (-3,-1)
