1.15 g of a metallic element reacts with 300cm3 of oxygen at 298K and 1 atm pressure, to form an oxide which contains O2– ions.
1 answer:
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Explanation:
to calculate theoratical yield...first we must calculate how much Sucrose moles we have..in order to to do so...we must calculate molar mass of sucrose.
molar mass of sucrose is 342.3 g/mol.
now we can calculate how many sucrose moles we have by dividing the mass with molar mass of sucrose
735g/(342.3g/mol)=2.147mol
theoratically...according to stoichiometry..every 1 mole of sucrose yields 4 moles of ethanol...so...
2.147mole yield 2.147*4mol=8.588mol
now we must calculate weight of that much ethanol..molar mass of ethanol is 46.07 g/mol...
so we can multiple moles by molar mass to obtain the weight 8.588mol*46.07g/mol=395.649g
but we only obtained 310.5g...so percentage we have is
78.47%
if there is trouble with molar mases I used....use what you calculated...
If my explanation is good enough...please mark it as brainliest.thanks