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m_a_m_a [10]
4 years ago
7

What is the vertex form of the equation y equals negative x squared + 12 x - 4

Mathematics
2 answers:
vitfil [10]4 years ago
8 0

Answer:

It's actually (-6, -40) but I'm not sure why or how

Step-by-step explanation:


Dominik [7]4 years ago
4 0
I think it may be (6,32)
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V125BC [204]

Answer:

rational

Step-by-step explanation:

8 0
3 years ago
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Aisha wants to make a dog bed for her new puppy. She buys 2.5 yards of fabric. If the fabric costs $4.90 per yard, how much does
balu736 [363]

Answer:

$12.25

Step-by-step explanation:

2.5 yards of fabric * $4.90 per yard of fabric = $12.25. Hope this helps!

3 0
3 years ago
Find the value of the missing segment below please.
kogti [31]

Answer:

Um it might be 1 but feel free to correct me if I'm wrong

7 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
Express 0.000216 in scientific notation
damaskus [11]
2.16 x 10 to the power of -4
3 0
3 years ago
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