What is 1/10 of an income of $97.50
2 answers:
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Answer:
The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.
Step-by-step explanation:
Let <em>X</em> = number of items with unacceptable quality.
The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.
The sample of items selected is of size, <em>n</em> = 150.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.
According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.
The mean of this sampling distribution is:
The standard deviation of this sampling distribution is:
If 10 of the 150 items produced are unacceptable then the probability of this event is:
Compute the value of as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.
Answer:
Step-by-step explanation:
Given in the question:
a) A family paid $96 for 4 pool passes and 2 gym memberships.
b) Later that day, an individual bought pool passes for herself and 2 of her friends , and 1 gym membership for her . She paid $60.
Let's write the system of equation for each purchase that happened in the scenario.
Let,
P= Price of each pool passes
G= Price of each gym membership
We get,
a) A family paid $96 for 4 pool passes and 2 gym memberships:
b) Later that day, an individual bought pool passes for herself and 2 of her friends , and 1 gym membership for her . She paid $60:
Therefore, the equations generated in the scenario were:
Where,
P=Price of each pool passes
G=Price of each gym membership
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