Answer:
a=1 or a=5
Step-by-step explanation:
+4=6a−1
Step 1: Subtract 6a-1 from both sides.
+4−(6a−1)=6a−1−(6a−1)
−6a+5=0
Step 2: Factor left side of equation.
(a−1)(a−5)=0
Step 3: Set factors equal to 0.
a−1=0 or a−5=0
a=1 or a=5
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Answer:
4
Step-by-step explanation:
Answer:
New cars sold = 20,
Used cars sold = 25
Cars serviced = 290
Step-by-step explanation:
In a month they sold fifteen less used cars than twice the number of new cars.
Lets say 'x' number of new cars were sold, then:
The number of used car sold is:

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

Solving for 'x' we get:




Therefore, the number of new cars sold in that month is 20.
Number of used car sold 
Number of cars serviced 
We can also cross check by summing them up:

Answer:
Step-by-step eEssential expenses most likely include:
Shelter.
Food and toiletries (this includes pet needs)
Utilities (this includes water, hydro, internet, etc.)
Car expenses.
Debt payments.
Insurances and medical needs.xplanation:
Answer:
3 AND 5
Step-by-step explanation:
LET THE TWO NUMBERS BE X AND Y
THEN
X + Y = 8 …….1
X – Y = 2 …… 2
WE SOLVE SIMULTANOUSLY
SUBTRACTNG EQATION 2 FROM 1
X – X + Y – (-Y) = 8 – 2
Y + Y = 6
2Y = 6
DIVIDING EACH TERM BY 2
2Y/2 = 6/2
Y = 3
THEN PUTTING Y = 3 IN EQUATION 1
X + 3 = 8
X = 8 – 3
X = 5