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nata0808 [166]
3 years ago
14

I don't understand how to further answer the question. Can somebody explain with an image of the work??

Mathematics
2 answers:
STatiana [176]3 years ago
4 0
-3x^2+12x-15=0
-3x^2+12x       =15
-3x^2+12x+36=15
lina2011 [118]3 years ago
3 0
-3(x^2+4x-5)
= -3(x-2)^2-3=0
this is ur answer 
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<h3>How to determine the hypotenuse?</h3>

<u>Step 1 and 2: Draw an isosceles right triangle</u>

See attachment (figure 1) for this triangle

The legs of this triangle have a length of 1 inch

<u>Step 3: The hypotenuse</u>

This is calculated using the following Pythagoras theorem

h^2 = 1^2 + 1^2

This gives

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<u>Step 4: Draw another isosceles right triangle</u>

Add 1 inch to one of the legs

See attachment (figure 2) for this triangle

The legs of this triangle have lengths of 1 inch and 2 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

h^2 = 2^2 + 1^2

This gives

h = \sqrt 5

<u>Step 5: Draw another isosceles right triangle</u>

Add 1 inch to one of the legs

See attachment (figure 3) for this triangle

The legs of this triangle have lengths of 1 inch and 3 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

h^2 = 3^2 + 1^2

This gives

h = \sqrt {10

<u>Step 6: Draw another isosceles right triangle</u>

Add 1 inch to one of the legs

See attachment (figure 4) for this triangle

The legs of this triangle have lengths of 1 inch and 4 inches, respectively

This hypotenuse is calculated using the following Pythagoras theorem

h^2 = 4^2 + 1^2

This gives

h = \sqrt{[17

See that the hypotenuse is the square root of 17

Hence, the right triangle whose legs are 1 inch and 4 inches has an hypotenuse of √17

Read more about right triangles at:

brainly.com/question/2437195

#SPJ1

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WHOEVER ANSWRS THE OTHER QUESTIONS IF YOU CLICK ON ME AND GO TO THE QUESTIONS I ASKED, I WILL MAKE YOU BRAINLEST WITH SOOOOOO MU
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thanks!

Step-by-step explanation:

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