23.0 + 60.0 = 83.0° C heat energy is required to raise
Answer:B) a reactant that undergoes reduction
Explanation:
Oxidation reaction is defined as the reaction in which a substance looses electrons. The oxidation state of the substance increases during oxidation.
Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced during reduction.

Overall reaction: 
The substance M which itself gets oxidized, reduces other and is called as reducing agent. The substance N which itself gets reduced, oxidizes other and is called as oxidizing agent.
Answer : The limiting reagent is 
Solution : Given,
Moles of methane = 2.8 moles
Moles of
= 5 moles
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 mole of
react with 1 mole of 
So, 5 moles of
react with
moles of 
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Hence, the limiting reagent is 
Answer:1) Volume of
required is 55.98 mL.
2) 0.62577 grams of
is produced.
Explanation:

1) Molarity of 
Volume of 
Molarity of 
Volume of 


According to reaction, 1 mole of
reacts with 3 mole of
, then, 0.0041985 moles of
will react with:
moles of
that is 0.0125955 moles.


Volume of
required is 55.98 mL.
2)

Number of moles of
According to reaction, 3 moles of
gives 1 mole of
, then 0.004485 moles of
will give:
moles of
that is 0.001495 moles.
Mass of
=
Moles of
× Molar Mass of 
= 0.001495 moles × 418.58 g/mol = 0.62577 g
0.62577 grams of
is produced.
Answer:
D.) 4
Explanation:
Al + 3 O₂ --> 2 Al₂O₃
In the equation, there are:
<em>Reactants:</em> 1 Al and 6 O
<em>Products:</em> 4 Al and 6 O
To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.
The new equation would look this this:
4 Al + 3 O₂ --> 2 Al₂O₃
There are now:
<em>Reactants:</em> 4 Al and 6 O
<em>Products:</em> 4 Al and 6 O