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Julli [10]
2 years ago
6

The mass percent of hydrogen in hydrogen peroxide, h2o2, is

Chemistry
2 answers:
Artemon [7]2 years ago
5 0

<u>Answer:</u> The mass percent of hydrogen in hydrogen peroxide is 5.88 %.

<u>Explanation:</u>

In H_2O_2, there are 2 hydrogen atoms and 2 oxygen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of hydrogen peroxide}}\times 100

Mass of hydrogen = (1\times 2)=2g

Mass of hydrogen peroxide = 34 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{2}{34}\times 100=5.88\%

Hence, the mass percent of hydrogen in hydrogen peroxide is 5.88 %.

miss Akunina [59]2 years ago
3 0
The atomic weight of H is 1, O is 16.
There are two of each in a hydrogen peroxide molecule.
(1*2)+(16*2)=2+32
2+32=34
The weight of the whole molecule is 34, and hydrogen makes up 2 of that.
(2/34)*100=0.0588235294*100
0.0588235294*100=5.88235294

The percentage mass of hydrogen in a hydrogen peroxide molecule is 5.88%
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<u>Answer:</u> The amount of carbon dioxide gas produced in the reaction is 83.6 grams

<u>Explanation:</u>

As, some amount of oxygen gas is left after the reaction is completed. So, it is present in excess and is considered as an excess reagent.

Thus, carbon is considered as a limiting reagent because it limits the formation of product.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

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By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of carbon dioxide gas

So, 1.9 moles of carbon will produce = \frac{1}{1}\times 1.9=1.9moles of carbon dioxide gas

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Molar mass of carbon dioxide = 44 g/mol

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Putting values in equation 1, we get:

1.9mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(1.9mol\times 44g/mol)=83.6g

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