____K + ___H2O → ___

You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially

nika2105 [10]

Answer :

(a) The heat released by the metal is -312.48 J

(b) The specific heat of the metal is $0.0944J/g^oC$

Explanation :

Heat released by the metal = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the metal

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $51.5J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 50.0 g

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-22.0=1.2^oC$

Now put all the given values in the above formula, we get:

$q=[(51.5J/^oC\times 1.2^oC)+(50.0g\times 4.184J/g^oC\times 1.2^oC)]$

$q=312.48J$

Thus, the heat released by the metal is -312.48 J

$q=m\times c\times \Delta T$

q = heat released by the metal = -312.48 J

m = mass of metal = 43.1 g

c = specific heat of metal = ?

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-100=76.8^oC$

Now put all the given values in the above formula, we get:

$-312.48J=43.1g\times c\times 76.8^oC$

$c=0.0944J/g^oC$

Thus, the specific heat of the metal is $0.0944J/g^oC$

8 0

4 years ago

The initial pressure of a gas is 1.58 atm and occupies 1.76 L of space at constant temperature. This gas is compressed so that i

jok3333 [9.3K]

Answer:

Final volume = 0.39 L

Explanation:

V1P1 = V2P2

V2= V1P1/P2

V2= (1.76×1.58)/7.08

V2 = 0.39 L

7 0

3 years ago

Calculate the molar solubility of lead thiocyanate in pure water. The molar solubility is the maximum amount of lead thiocyanate

OLga [1]

Answer:

$Molar solubility(S)=1.71\times10^{-2} mole/litre$

Explanation:

Assume Ksp of $Pb(SCN)_{2}$ = $2\times10^{-5}$ ( it is general value ,i took it because not given in question)

molar solubilty means how much maximum mole of lead thiocynate is dissolved in one litre of solvent.

Ksp=solubility product;

$Pb(SCN)_2= Pb^{2+} +2SCN^-$

Lets molar solubilty of $Pb(SCN)_2$ is S then

$[Pb^{+2}]=S;$

$[SCN^{-1} ]=2S;$

$Ksp =S\times(2S)^{2} =2\times10^{-5}$

$4S^{3}=2\times10^{-5}$

$S=1.71\times10^{-2} mole/litre$

4 0

3 years ago

How many grams of ZnO would you need to produce 50 g of ZnCl2? (The atomic mass of Zn is 65.38 and of Cl is 35.45.) ZnO(s) + 2HC

marta [7]

.37 grams of ZnO

hope this helps!

4 0

3 years ago

Which way will the equilibrium shift if you..... cool it to a low temperature?

igor_vitrenko [27]

If you can provide the reaction you are looking at, then we can provide a more satisfactory answer.

If the forward reaction is exothermic, then reducing the temperature where the reaction occurs will shift the equilibrium towards the right. This is because exothermic reactions release heat, and this will counteract the change as stated in Le Chatelier's Principle.

If the forward reaction is endothermic, then reducing the temperature will shift to the left. This occurs as the backward reaction is the exothermic reaction, and by Le Chatelier's Principle, the reaction will favor the reaction that produces more in to counter a reduction in temperature, in this case the backward direction reaction.

5 0

3 years ago

____​K + ​___​H​2​O → ​____​KOH + H​2

__K + _H2O → ____KOH + H2