E = m c²
where E = energy released
m = mass of the nucleus
C= velocity of light
m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg
C = 3 x 10⁸ m/s and C² = 9 x 10¹⁶
E = 1.37 x 10 ⁻¹² J
Answer:2 AL + FEN2 = 2 ALN + FE
Explanation: AL might be an improperly capitalized: Al. One of your compounds is AL (A and L). Did you mean Al (aluminum)?
FEN2 might be an improperly capitalized: FeN2. ALN might be an improperly capitalized: AlN
FE might be an improperly capitalized: Fe
It's 6.
2(NH4)3PO4
The three outside the parenthesis means 3 NH4 groups. The coefficient of 2 means two entire formula units of 2(NH4)3PO4
That's 6 NH4 groups (2 x 3) making 6 N atoms.
How many H atoms? 4 x 3 x 2 = 24
2 P and 8 O
Answer:
There are fifteen molecular orbitals in benzene filled with electrons.
Explanation:
Benzene is an aromatic compound. Let us consider the number of bonding molecular orbitals that should be present in the molecule;
There are 6 C-C σ bonds, these will occupy six bonding molecular orbitals filled with electrons.
There are 6 C-H σ bonds, these will occupy another six molecular orbitals filled with electrons
The are 3 C=C π bonds., these will occupy three bonding molecular pi orbitals.
All these bring the total number of bonding molecular orbitals filled with electrons to fifteen bonding molecular orbitals.