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Savatey [412]
3 years ago
7

What is the product? (3a^2b^7)(5a^3b^8)

Mathematics
1 answer:
vitfil [10]3 years ago
4 0
15a^5 b^15 Is The Answer 
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GalinKa [24]
The answer is (D) ....
6 0
3 years ago
Read 2 more answers
Find the difference: 11 - 4.7
shutvik [7]

<u><em>Answer: 6.3 *The answer must be have a decimal point.*</em></u>

Explanation:

First, subtract by the numbers. Subtract it's going to be find the difference between the numbers.

11-4.7=6.3

You can also add by the numbers.

6.3+4.7=11

11-6.3=4.7

Hope this helps!

Thank you!

Have a great day!

7 0
3 years ago
Read 2 more answers
Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's
Tom [10]

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

=\frac{5}{94}\times 100

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer



5 0
3 years ago
Read 2 more answers
What is the distance between (5,2) and (1,-3) on a coordinate plane?
Citrus2011 [14]
I believe it would be (4,5)
6 0
3 years ago
Read 2 more answers
Mia is tracking her savings account balance . She knows the equation to find her balance y in any year t, but she can't remember
motikmotik

Complete question is;

Mia is tracking her savings account balance. She knows the equation y = 8000p^(t) can be used to find her balance y in any year t, but she can't remember what p represents. Her balance 3⅔ years after opening her account, is $9,905.54. What is the value of p?

Answer:

p = 1.06

Step-by-step explanation:

We are told that the equation y = 8000p^(t) can be used to find her balance y in any year t.

Now, we are given t = 3⅔ = 11/3 years

Also, we are given balance after 11/3 years as;

y = $9,905.54

Thus;

Plugging the relevant values into y = 8000p^(t), we have;

9,905.54 = 8000p^(11/3)

p^(11/3) = 9905.54/8000

p = (9905.54/8000)^(3/11)

p = 1.06

4 0
3 years ago
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