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Anna35 [415]
4 years ago
7

What is the distance between the center of the circle with equation x^2+y^2=2x+4y-1 and the point (13,7)?

Mathematics
1 answer:
Marizza181 [45]4 years ago
6 0
The answer is 13. Hope this helps

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Recall the formula from Lesson 3.2 used to find Jenna’s cost to drive her own car for work. In this formula, J= Cost of driving
Vedmedyk [2.9K]

Answer:

Cost of driving Jenna's car is $0.293 per mile when the price of gas is $3.23 per gallon.

Step-by-step explanation:

Expression given in the question is not correct, it is actually

J=\frac{g}{22}+0.146

Since expression that represents Jenna's cost to drive her car for work is

J=\frac{g}{22}+0.146

Where J = cost of driving Jenna's car

g = cost of gas

We have to find the cost of driving Jenna's car when the price of gas is $3.23 per gallons.

Now we plug in the value of g = $3.23 per gallon in the given expression.

J=\frac{3.23}{22}+0.146

  = 0.1468 + 0.146

  = 0.2928

  ≈ $0.293 per mile

Therefore, cost of driving Jenna's car is $0.293 per mile when the price of gas is $3.23 per gallon.  

7 0
4 years ago
If two supplementary angles is in the ratio 7:8 find the complement of the smaller angle​
schepotkina [342]

Answer:

6°

Step-by-step explanation:

Let

the supplementary angles be 7x and 8x  so,

7x+8x=180  ,15x=180  ,x=180/15  ,x=12

smaller angle=7x=7×12=84°

complement of 84°=90°-84°=6°

7 0
3 years ago
23) Find 12 1/2% of 2 dozen​
Ipatiy [6.2K]

Answer:

3

Step-by-step explanation:

To find 12.5% of 2 dozen

We convert 2 dozen into a number which would be:

2×1 dozen (1 dozen = 12)

2×12=24

12.5% of 24 will be

10% of 24 will be 24÷10=2.4

2.5% will be 1/4 of 10%

2.5% = 2.4÷4

2.5%=0.6

12.5%=0.6+2.4

12.5%=3

5 0
3 years ago
A. 5/8<br><br> B. -8/5<br><br> C. 8/5<br><br> D. -5/8
Alexus [3.1K]

Answer:

A

Step-by-step explanation:

nsjsnsnsjsbsbjsbshshsbsjusbbbsjsj

4 0
3 years ago
Why does it help to rearrange
hichkok12 [17]

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

8 0
3 years ago
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