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mariarad [96]
3 years ago
7

If the intensity of a loud car horn is 0.005 W/m^2 when you are 2 meters away from the source. Calculate the sound intensity lev

el. A. 1.6 W
B. 0.06 W
C. 97 dB
D. 223 dB
E. 179 dB
Physics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

(c) 97 dB sound intensity level

Explanation:

We have given the intensity of the loud car horn I=0.005w/m^2

We know that I_O=10^{-12}w/m^2

Now the sound intensity level is given by \beta =10log\frac{I}{I_0}=10log\frac{0.005}{10^{-12}}=96.98dB , which is nearly equal to 97

So the sound intensity level will be 97 dB

So option (c) will be the correct option

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Answer:

The appropriate solution is "61.37 s".

Explanation:

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Now,

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Travelling such distance for 300 m will be:

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⇒ v=\frac{v}{t} \ sot \ t

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On putting the values, we get

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hence,

The time taken by the boat will be:

= 26.08+35.29

= 61.37 \ s

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