According to diagonal rule, the orbital with lowest energy in the given following is _______

Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive

Burka [1]

Answer:

$1.91773\times 10^{37}\ kg$

Explanation:

v = Orbital speed = 130 km/s

d = Diameter = 16 ly

r = Radius = $\dfrac{d}{2}=\dfrac{16}{2}=8\ ly$

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$1\ ly=9.461\times 10^{15}\ m$

As the centripetal force balances the gravitational energy we have the following relation

$\dfrac{GMm}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow M=\dfrac{v^2r}{G}\\\Rightarrow M=\dfrac{130000^2\times 8\times 9.461\times 10^{15}}{6.67\times 10^{-11}}\\\Rightarrow M=1.91773\times 10^{37}\ kg$

Mass of the the massive object at the center of the Milky Way galaxy is $1.91773\times 10^{37}\ kg$

4 0

3 years ago

A swimmer of mass 64.38 kg is initially standing still at one end of a log of mass 237 kg which is floating at rest in water. He

nikklg [1K]

Answer:

0.9432 m/s

Explanation:

We are given;

Mass of swimmer;m_s = 64.38 kg

Mass of log; m_l = 237 kg

Velocity of swimmer; v_s = 3.472 m/s

Now, if we consider the first log and the swimmer as our system, then the force between the swimmer and the log and the log and the swimmer are internal forces. Thus, there are no external forces and therefore momentum must be conserved.

So;

Initial momentum = final momentum

m_l × v_l = m_s × v_s

Where v_l is speed of the log relative to water

Making v_l the subject, we have;

v_l = (m_s × v_s)/m_l

Plugging in the relevant values, we have;

v_l = (64.38 × 3.472)/237

v_l = 0.9432 m/s

8 0

2 years ago

PLEASE HELP!! Which of the following is a way the jet stream influences weather?

aniked [119]

The answer is C ......

4 0

3 years ago

Read 2 more answers

Suppose you have avogadro\'s number of mini marshmallows and use them to cover the state of california which has a land area of

Marta_Voda [28]

Avogadro's number is equal to 6.02 E 23

Thie means we have 6.02 E 23 marshmallows.

Assuming each marshmallow to be a small cylinder we can calculate the area of its base

Area circumference = pi*r² = pi * (0.635/2)² = 0.317 cm²

So, 6.02 E 23 marshmallows * 0.317 cm² cover a total area of

Area covered = 1.908 E 23 cm² = 1.908 E 13 km²

<span>The land area of california is 1.560 E 5 mi</span>² = 4.04 E 5 km²

If we divide the Areas >>>>

1.908 E 13 km² / 4.04 E 5 km² = 47. 227 E 6 (This is the number of times the area of California could be filled with those marshmallows)

Now for the height, we multiply this number times the height of each marshmallow

47. 227 E 6 * 2.54 cm = 119.96 E 6 cm = 1199.6 km above the surface

6 0

3 years ago

A number of compounds containing the heavier noble gases, and especially xenon, have been prepared. One of these is xenon hexafl

aalyn [17]

Answer:

The answer is "82.2 torr"

Explanation:

moles of Xe:

$= \frac{0.06}{131.293} \\\\ =0.00045699313 \ \mol$

moles of $F_2$ :

$= \frac{0.0274}{38} \\\\= 0.00072105263\ \ mol$

moles of produced $XeF_2:$

$= 0.00024$

moles of left $Xe$ :

$= 0.00021$

Calculate the Pressure:

$= \frac{(0.08206\times 0.00024 \times 293)}{(.1)} + \frac{(0.08206\times 0.00021 \times 293)}{(.1)} \\\\= 0.10819611 \ \ atm \\\\ = 0.10819611 \times 760 \\\\ = 82.2 \ \ torr$

5 0

2 years ago

According to diagonal rule, the orbital with lowest energy in the given following is ________.