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Maslowich
3 years ago
8

According to diagonal rule, the orbital with lowest energy in the given following is ________.

Physics
1 answer:
Kaylis [27]3 years ago
5 0
The orbital with the lowest energy is 3s.
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When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their
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Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

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Now this causes a centripetal acceleration

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qvB = mv^2/r ...........(i)

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If  accelerating potential V is  same and  then  kinetic energy equals the potential energy difference

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simplifying we get  

B =m \frac{(\sqrt{ 2Vm/q})}{r}

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B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}      ..............(iii)

B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}    ..........(iv)

 dividing (iv) and (iii) equation we get

\frac{B_{10}}{B_{7}}   =   \sqrt{\frac{m_{10}}{{m_7}} }

{B_{10}}  =  B_{7}  \sqrt{\frac{m_{10}}{{m_7}} }

B_{10}       = 0.2574T\sqrt{\frac{  (1.663x10^-26}{(1.165x10^-26)}

so on solving we get  

             =0.3075 T

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