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Maslowich
3 years ago
8

According to diagonal rule, the orbital with lowest energy in the given following is ________.

Physics
1 answer:
Kaylis [27]3 years ago
5 0
The orbital with the lowest energy is 3s.
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How much time does it take a trucker to deliver his shipment 480 km away travelling at an average speed of 120 km/hr?​
kifflom [539]

Answer: time=4 hours

Explanation:

formula:

speed = \frac{distance}{time}

time = \frac{distance}{speed}

time= x

speed = 120km/hr

distance = 480 km

x = \frac{480 km}{120km/hr\\}

=\frac{48km*hr}{12km}

cut the zeros

and remove the signs

then

\frac{48}{12} = 4

therefore, time taken to deliver the shipment by trucker is 4 hours

8 0
3 years ago
Suppose two vectors have unequal magnitudes. can their sum be zero? explain
GalinKa [24]

Answer;

-  No, Two vectors of unequal magnitude can never sum to zero.

Explanation;

-Two vectors of equal magnitude that are pointing in opposite directions will sum to zero.

-Two vectors of unequal magnitude can never sum to zero. If they point along the same line, since their magnitudes are different, the sum will not be zero.

- If they point in different directions, then you can always decompose one vector into two components: one along the other vector and one perpendicular to the other vector. In this case, the perpendicular component can never be eliminated.

5 0
3 years ago
A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?
bixtya [17]

Answer:42.43m/s

Explanation:According to vf=vi+at, we  can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s

4 0
1 year ago
13. Direct instruction takes place when
jekas [21]
A skill set is explicitly taught or an activity is completed
3 0
4 years ago
A loaded barge has a mass of 1 500 000 kg and is traveling at 3 m/s. If a tugboat applies an opposing force of 12 000 N for 10 s
yan [13]

Answer:

Explanation:

Initial momentum is 1.5e6(3) = 4.5e6 kg•m/s

An impulse results in a change of momentum

The tug applied impulse is 12000(10) = 120000 N•s or 0.12e6 kg•m/s

The remaining momentum is 4.5e6 - 0.12e6 =  4.38e6 kg•m/s

The barge velocity is now 4.38e6 / 1.5e6 = 2.92 m/s

The tug applies 0.012e6 N•s of impulse each second.

The initial barge momentum will be zero in

t = 4.5e6 / 0.012e6 = 375 s or 6 minutes and 15 seconds

To stop the barge in one minute(60 s), the tug would have to apply

4.5e6 / 60 = 75000 N•s /s or 75 000 N

5 0
2 years ago
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