Find the acceleration due to gravity on the surface of Mars. The
1 answer:
Answer:
The acceleration due to gravity on the surface of Mars is approximately 3.773 m/s²
Explanation:
The given parameters for Mars with guidance from online search are;
The mass, m = 6.42 × 10²³ kg
The given radius of Mars, r = 3,370 km = 3,370,000 m
The gravitational constant, G = 6.674 × 10⁻¹¹ N·m²/kg²
Therefore, we have, the acceleration due to gravity on the surface of Mars, given as follows;
= G × m/r² = 6.674 × 10⁻¹¹ × 6.42 × 10²³/(3,370,000)² ≈ 3.773
The acceleration due to gravity on the surface of Mars, ≈ 3.773 m/s².
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Answer:
0.075 T
Explanation:
When a current-carrying wire is immersed in a region with magnetic field, the wire experiences a force, given by
where
I is the current in the wire
L is the length of the wire
B is the strength of the magnetic field
is the angle between the direction of I and B
In this problem we have:
L = 0.65 m is the length of the wire
I = 8.2 A is the current in the wire
F = 0.40 N is the force experienced by the wire
since the current is at right angle with the magnetic field
Solving the formula for B, we find the strength of the magnetic field: